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4 years ago

Explain how you would use equivalent fractions to solve 0.5 + 0.10

2 answers:

8 0

.5 half of a whole so it is 1/2 .10 is 1/10 you want the same number on the bottom part of the fraction (denominator) so covert 1/2 to 5/10 and now you have 5/10 + 1/10 and that is 6/10.

Lelechka [254]4 years ago

6 0

5/10+1/10=6/10, they are equivalent since the denominator is the same :)

You might be interested in

Evaluate each function following the specification.

telo118 [61]

Answer:

#3 a. g(-1) = 2, g(0) = 3, and g(1) = 2

b. No restrictions for all real numbers

$\#4 \ a. \ h(-1) = \dfrac{1}{3}, \ h(0) =0, \ h(2) = \infty$

b. Yes, <em>x ≠ 2</em>

Step-by-step explanation:

#3 The function is given as g(x) = -x² + 3

a. From the given function, by plugging in the value of 'x' in the bracket, we have;

g(-1) = -(-1)² + 3 = -1 + 3 = 2

g(-1) = 2

g(0) = -0² + 3 = 3

g(0) = 3

g(1) = -1² + 3 = -1 + 3 = 2

g(1) = 2

g(-1) = 2, g(0) = 3, and g(1) = 2

b. The given function g(x) = -x² + 3 for finding the value of <em>g</em> can take any value of <em>x</em> which is a real number

Therefore, therefore, there are no restrictions

#4 a. The given function is given as follows;

$h(x) = \dfrac{x}{x - 2}$

By substitution, we get;

$h(-1) = \dfrac{-1}{(-1) - 2} = \dfrac{-1}{-3} = \dfrac{1}{3}$

$\therefore h(-1) = \dfrac{1}{3}$

$h(0) = \dfrac{0}{0 - 2} = \dfrac{0}{-2} =0$

$\therefore h(0) =0$

$h(2) = \dfrac{2}{2 - 2} = \dfrac{2}{0} = \infty$

$\therefore h(2) = \infty$

$h(-1) = \dfrac{1}{3}, \ h(0) =0, \ h(2) = \infty$

b. From the values of the function, we have that h(x) is not defined at x = 2

Therefore, there is a restriction for <em>x</em> in the function, which is <em>x ≠ 2</em>

3 0

3 years ago

PLEASE HELP

Lemur [1.5K]

1. y=6

2. y=-12

Step-by-step explanation:

<u>1) If y varies inversely as x, and y=3 as x = -2, find y for the x value of -1.</u>

It is given that

y varies inversely as x

IT will be written as:

y∝1/x

Removing the proportionality symbol

y=k/x

Given

y=3 , x=-2

Putting the values

3=k/-2

k=3*-2 = -6

The equation will be:

y=-6/x

So,

When x=-1

$y=\frac{-6}{-1}\\y=6$

<u>2) If y varies directly as x, and y=15 as x=-3, find y for the x value of 4</u>

y is directly proportional to x

y∝x

y=kx

Given

y=15, x=-3

Putting the values

$y=kx\\15=-3k\\k=\frac{15}{-3}\\k=-5\\The\ equation\ will\ be:\\y=-3xNow,\\x=4\\y=-3(4)\\y=-12$

Hence,

1. y=6

2. y=-12

Keywords: Proportion, Variation

Learn more about proportion at:

#LearnwithBrainly

8 0

3 years ago

Not sure f either of my answers would satisfy the question in the second picture

xz_007 [3.2K]

$\bf \begin{array}{llll}
tan(\alpha)=-\cfrac{80}{15}\qquad II\\\\
x=-15\\
y=8\\
r=17
\end{array} \qquad \qquad 
\begin{array}{llll}
cos(\beta)=\cfrac{5}{6}\qquad I\\\\
x=5\\
y=\sqrt{11}\\
r=6
\end{array}\\\\
-----------------------------\\\\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\\\\\
sin({{ \alpha}} + {{ \beta}})=\cfrac{8}{17}\cdot \cfrac{5}{6}+\cfrac{-15}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{40-15\sqrt{11}}{102}$

$\bf cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})
\\\\\\
\cfrac{-15}{17}\cdot \cfrac{5}{6}-\cfrac{8}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{-75-8\sqrt{11}}{102}$

$\bf tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) = \cfrac{-\frac{8}{15}+\frac{\sqrt{11}}{5}}{1-\left( -\frac{8}{15}\cdot \frac{\sqrt{11}}{5} \right)}\implies 
\cfrac{\frac{-8+3\sqrt{11}}{15}}{1+\frac{8\sqrt{11}}{75}}
\\\\\\
tan({{ \alpha}} + {{ \beta}}) =\cfrac{\frac{-8+3\sqrt{11}}{15}}{\frac{75+8\sqrt{11}}{75}}\implies \cfrac{-8+3\sqrt{11}}{15}\cdot \cfrac{75}{75+8\sqrt{11}}
\\\\\\
$

$\bf tan({{ \alpha}} + {{ \beta}}) =\cfrac{-8+3\sqrt{11}}{1}\cdot \cfrac{3}{75+8\sqrt{11}}\implies \cfrac{15\sqrt{11}-40}{75+8\sqrt{11}}$

6 0

4 years ago

PLEASE ANSWER FAST!!! Eloise's rabbit cage is shaped like a rectangular prism. The cage has a height of 28 inches and a volume o

lisabon 2012 [21]

The area of the plastic mat on the bottom of the cage is 310 inches²

Step-by-step explanation:

Eloise's rabbit cage is shaped like a rectangular prism

The cage has a height of 28 inches
Its volume is 8,680 cubic inches
Eloise bought a plastic mat for the bottom of the cage, the plastic mat fits the bottom of the cage perfectly

We need to find the area of the plastic mat on the bottom of the cage

The volume of a rectangle prism = area of base × its height

∵ The height of the cage = 28 inches

∵ The volume of the cage = 8,680 inches³

- Substitute them in the rule of the volume above

∴ 8680 = area of base × 28

- Divide both sides by 28

∴ 310 = area of the base

∴ The area of the base of the cage is 310 inches²

∵ The plastic mat fits the bottom of the cage

- That means the area of the plastic mat is equal to the area

of the bottom of the cage

∴ The area of the plastic mat = 310 inches²

The area of the plastic mat on the bottom of the cage is 310 inches²

Learn more:

You can learn more about the volume in brainly.com/question/12497249

#LearnwithBrainly

7 0

3 years ago

Hey cozycooljoe can you help me with this also, I am not rlly in High School I am in 7th Grade Jr. High.

jasenka [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers