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zloy xaker [14]
3 years ago
15

Explain how you would use equivalent fractions to solve 0.5 + 0.10

Mathematics
2 answers:
Andrew [12]3 years ago
8 0
.5 half of a whole so it is 1/2 .10 is 1/10 you want the same number on the bottom part of the fraction (denominator) so covert 1/2 to 5/10 and now you have 5/10 + 1/10 and that is 6/10.
Lelechka [254]3 years ago
6 0
5/10+1/10=6/10, they are equivalent since the denominator is the same :)
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Audrey is saving for a school trip. She needs
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i think 300$

Step-by-step explanation:

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2 years ago
brainliest goes to whoever answers the question correctly also if you want more points answer my other questions
Sergeeva-Olga [200]

Answer:

A and B are functions

Step-by-step explanation:

for A, none of the x's repeat which makes it a FUNCTION

for B, when it starts with x^2, it will always be a FUNCTION (its a quadratic)

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2 years ago
Barrett works at an ice cream shop. The function f(x) represents the amount of money Barrett earns per gallon of ice cream, wher
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The value of f(g(x)) is 6x^{3} +4

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f(x)=2x^{2} +4

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g(x)=\sqrt{3x^{3} }

To determine the value of f(g(x)), let us first substitute the value of g(x).

Thus, we get,

f(g(x))=f(\sqrt{3x^{3} } )

Now, substituting for x=\sqrt{3x^{3} } in the function f(x), we get,

f(g(x))=2(\sqrt{3x^{3} } )^2+4

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f(g(x))=2({3x^{3} } )+4

Multiplying the term within the bracket, we have,

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2 years ago
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

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We have the standard deviation for the sample, so we use the t-distribution to solve this question.

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90% confidence interval

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The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

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The 90% confidence interval for the mean test score is between 77.29 and 85.71.

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Answer:

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