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2 years ago

Some one teach me how to do this I’m in a break out room and I don’t know how to do this

Mathematics

1 answer:

Murljashka [212]2 years ago

8 0

Answer:

start by putting in the y intercept, -4 on the y axis

then go up 5 and 1 right one to give your a slope of positive 5

Step-by-step explanation:

<h2><u>porque yo so muy inteligente,</u></h2><h2><u>la reina... </u></h2>

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Application Question:

Alika [10]

When you add 4 to 25 you get 21 then subtract 11 and get 10 and then add 15 which is equal to 25 and then subtract 13.

the answer is 12

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2 years ago

How long does it take for a car to travel 250 feet at 35 mph?

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3 years ago

Choose the correct simplification of x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4t

Umnica [9.8K]

Answer:

<h3>The option A) $x^{10}z^7$ is correct answer.</h3><h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3>

Step-by-step explanation:

Given expression is x to the 12th power times z to the 11th power all over x to the 2nd power times z to the 4th power.

The given expression can be written as $\frac{x^{12}\times z^{11}}{x^2\times z^4}$

<h3>To choose the correct simplification of the given expression :</h3>

Now we have to simplify the given expression as below

$\frac{x^{12}\times z^{11}}{x^2\times z^4}$

$=x^{12}\times z^{11}(x^{-2}\times z^{-4})$ ( by using the identity $\frac{1}{a^m}=a^{-m}$ )

$=(x^{12}.x^{-2})\times (z^{11}.z^{-4})$

$=x^{12-2}\times z^{11-4}$ ( by using the identity $a^m.a^n=a^{m+n}$ )

$=x^{10}\times z^7$

$=x^{10}z^7$

∴ $\frac{x^{12}\times z^{11}}{x^2\times z^4}=x^{10}z^7$

<h3>The correct simplification for the given expression $\frac{x^{12}\times z^{11}}{x^2\times z^4}$ is $x^{10}z^7$ </h3><h3>Hence option A) $x^{10}z^7$ is correct answer.</h3>

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3 years ago

A and B are n×n matrices. Check the true statements below: A. (detA)(detB)=detAB. B. The determinant of A is the product of the

Rudik [331]

Answer with Step-by-step explanation:

We are given that

A and B are matrix.

A.We know that for two square matrix A and B

Then, $det(AB)=det(A)\cdot det(B)$