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snow_lady [41]
3 years ago
5

PLEASE ANSWER QUICK!!! WILL MARK BRAINLEIST!!!

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0
I think it is 4 pi............
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-2x + y = 4<br> y = x + 2<br><br><br> Third question^ solve the system of equations
Leya [2.2K]

Answer:

x=-2 y=0

Step-by-step explanation:

put the second equation in to the first one

-2x+x+2=4

-x=2

x=-2

y=-2+2=0

x=-2 y=0

6 0
3 years ago
What is the missing constant term in the perfect square that starts with x2 – 16x?
andre [41]

Answer:

64

Step-by-step explanation:

the expression is

x² - 16x + _

the constant term is the square of the number residing with x divided by 2

the number number x = 16

therefore the constant term is (16/ 2)²

= 8²

= 64

the formula being used here is

(x + a)² = x² + 2ax + a²

4 0
3 years ago
Subtract 65 from the product of 20 and 4.​
Klio2033 [76]

Answer:

15 is the answer

Step-by-step explanation:

20×4=80

80-65=15

3 0
2 years ago
Read 2 more answers
Write the quadratic equation whose roots are 1 and -2, and whose leading coefficient is 3.
kirill115 [55]

Answer:

  • See below

Step-by-step explanation:

<u>The quadratic equation in factored form:</u>

  • a(x - α)(x - β), where a- leading coefficient, α and β - roots

<u>We have:</u>

  • a = 3, α = 1, β = -2

<u>Substitute them to get:</u>

  • 3(x - 1)(x + 2)

<u>Converting this into standard form:</u>

  • 3(x - 1)(x + 2) =
  • 3(x² + x - 2) =
  • 3x² + 3x - 6
3 0
3 years ago
Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the end behavior.
jenyasd209 [6]
The function is f(x)=x^3-11x^2+36x-36.

To find the x-intercepts, we need to factorize the function. A very good idea is to first try the factors of 36:

f(1)=1-11+36-36, not 0

f(2)=8-44+72-36=-36+72-36=0. Here we have our first root (2).

Now we cad divide f(x) by (x-2) which will give us a quadratic expression, which we can factorize easily (if the discriminant is non negative).

We can also try some other factors of 36. Indeed we can check that 

f(3)=27-99+108-36=135-135=0, 
and
f(6)=216-396+216-36=0.

Thus, f(x)=(x-2)(x-3)(x-6). Note that if we expanded the right hand side expression, the constant term would be the product of the constants 2, 3, 6.

This is the reason why in the first place we looked at the factors of 36 for the possible zeros of f(x).


Thus, the x-intercepts are (2, 0), (3, 0), (6, 0), or 2, 3, 6. 

The y-intercept is f(0), which is -36.


Note that f(0)<f(2) because f(0)=-36 and f(2)=0. This means that at the left side, the graph is coming from - infinity. Similarly, 

we can check that f(10)=1000-1100+360-36=224> f(6). That is, to the right of our rightmost root, the graph is getting larger.

Thus, the end behaviors are: the graph goes to + infinity as x goes to + infinity, 

and it goes to minus infinity as x goes to - infinity.
7 0
3 years ago
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