Answer:- B:
is the right answer.
Solution:- The balanced equation is:

We have been given with 8.75 grams of oxygen and asked to calculate the grams of hydrogen needed to react with given grams of oxygen according to the balanced equation.
From balanced equation, 1 mole of oxygen reacts with 2 moles of hydrogen.
So, let's convert grams of oxygen to moles and multiply it by the mole ratio to calculate the moles of hydrogen that are easily converted to grams on multiplying by it's molar mass.
The complete set up looks as:

= 
Hence, the right option is B:
.
Answer:
Mass of Ca in sample, Mass of Br in sample, Number of moles of Ca in sample, Number of moles of Br in sample, Mass or moles of element other than Ca or Br in sample
Explanation:
The AP Classroom will not count your answer to this question as correct unless it includes at least one of the answers listed above. If you say that theanswer to this question is density, it will be marked as incorrect, I found that out the hard way when I used the answers that brainly gave me.
Good luck,
I applaud you for using the sources avalible to you, which is /definetly not/ cheeting.
Unicellular organisms...
Contain a single cell in their body
Do not contain membrane bound organelles
Use simple diffusion as a transport mechanism
All cellular processes are carried out by the single cell
Only visible under the microscope
Injury in the cell leads to the death of the organism
Asexually reproduce by binary fission
Sexually reproduce by conjugation
Lifespan is comparatively short
To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in liters. Note that the volume is in liters of solution and not liters of solvent. When a molarity is reported, the unit is the symbol M and is read as “molar”.
I hope this helped :)
Please make me the branliest! Have a good night/ good day!!
If matters mix and it doesn’t make a material it’s called physical change. But, if maters are mixed and they do make a material it’s called chemical change.