Answer:
Explanation:
a. Oxidation : 2O + 4e^- ------> 2O^2-
b. Reduction: 2Sr - 4e- -------> Sr^2+
c. Balanced redox reaction
2Sr + O2 ------------> 2Sr O
Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.
In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.
In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.
In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.
Answer:
when the pH increases suddenly in the flask
Explanation:
I think it's right. :)
The electron sea model for metals suggest that the valence electrons drift freely around the metal cations.
Answer: B
Explanation
The sea model of electron is used for describing the mechanism of metallic bonding.
The metallic bonding generally occurs between 2 or more metals leading to the formation of alloys.
According to electron sea model, the electrons which contributes to the metallic bond are mostly the valence electrons of the atoms, these valence electrons get de-localized and can move freely around the nuclei of other atoms.
Overall, it seems like nuclei of positive charge is surrounded by sea of negative electrons.
B. The energy barrier between reactants and products
hope this helps!
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