Can u guys help me with this question.
1 answer:
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Answer:
11250 N/C
Direction: 0 deg counterclockwise from positive x-axis
Explanation:
= magnitude of charge on each particle = 5 μC = 5 x 10⁻⁶ C
= distance of each particle from center of circle = 2 m
= Magnitude of electric field at the center by each particle
Magnitude of electric field at the center by each particle is given as
inserting the values
From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.
So net electric field at center is only due to charge q₂ direction towards positive x-direction
So
= Resultant electric field = 11250 N/C
Direction: 0 deg counterclockwise from positive x-axis
Answer:
the magnitude of the dog's total displacement to the nearest tenths = 53.12°
Explanation:
Given that:
a dog walks 8.0m due to the north and 6.0 m due east.
We can determine the magnitude of the dog's total displacement by using the Pythagoras theorem.
Consider the north direction be the opposite and the east direction to be the adjacent, therefore the hypotenuse will be the dog's total displacement.
So, suppose hypotenuse is represented by a
the opposite represented by b, and the adjacent represented by c
Then;
a² = b² + c²
a² = 8² + 6²
a² = 64 + 46
a² = 100
a =
a = 10.0 m
However, the magnitude of the dog's total displacement is calculated by taking the tangent of the system.
tan θ = opposite / adjacent
tan θ = b/c
tan θ = 8/6
tan θ = 4/3
tan θ = 1.333
θ = tan⁻¹ (1.333)
θ = 53.12
the magnitude of the dog's total displacement to the nearest tenths = 53.12°