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murzikaleks [220]
3 years ago
5

The white dwarf that remains when our sun dies will be mostly made of

Physics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

Carbon and oxygen

Explanation:

White dwarfs are the stars which have used all their hydrogen and helium fuel and now exists with only carbon and oxygen in their core. Their size reduces up to one hundredth times of the size of their sun in early stages and yet they possess the same mass.  

Due to loss of fuels and impact of gravity, a young star collapses on itself leading to formation of dwarf star.

 

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Planet A has a mass of 2.25 x 1020 kg, while planet B has a
denis23 [38]

The gravitational attraction between two planets is  4905.95 N

<h3>What is gravitational attraction?</h3>

When two objects with masses are placed at a distance, there will an attractive force acting between them.

According to the Newton's law of gravitation, gravitational force is

F = Gm₁m₂ /r²

where r is the distance between the masses m₁ and m₂ and  G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²

Substitute the values into the expression, we get

F =  6.67 x 10⁻¹¹ x  2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²

F= 4905.95 N

Thus, the gravitational attraction between two planets is  4905.95 N.

Learn more about gravitational attraction.

brainly.com/question/19822389

#SPJ2

6 0
2 years ago
Read 2 more answers
Objects with masses of 120 kg and a 420 kg are separated by 0.380 m. (a) Find the net gravitational force exerted by these objec
SOVA2 [1]

Answer:

F_{net} = 6.879\times 10^{- 7}\ N

Solution:

As per the question:

Mass of first object, m = 120 kg

Mass of second object, m' = 420 kg

Mass of the third object, M = 69.0 kg

Distance between the m and m', d = 0.380 m

Now,

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:

F = \frac{GMm}{\frac({d}{2}^{2})}

F = \frac{6.67\times 10^{-11}\times 120\times 0.69}{\frac({0.380}{2}^{2})} = 1.529\times 10^{- 7}\ N

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':

F = \frac{GMm}{\frac({d}{2}^{2})}

F' = \frac{6.67\times 10^{-11}\times 420\times 0.69}{\frac({0.380}{2}^{2})} = 5.35\times 10^{- 7}\ N

To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':

F_{net} = F + F'

F_{net} = 1.529\times 10^{- 7} + 5.35\times 10^{- 7} = 6.879\times 10^{- 7}\ N

6 0
3 years ago
A current runs to the right in a long, straight wire. What is the direction of the
SIZIF [17.4K]

Answer:

Into the page (Answer B)

Explanation:

Recall that the magnetic field that is created around a current conducting wire follows the right hand rule, where the direction of your fingers point in the direction of the magnetic field vectors when your thumb points in the direction of the current flow.

Use this to see that as you place the thumb of your right hand on the page pointing to the right (direction of the current in the wire). As you do so, you find the four fingers of your right hand entering the paper.

7 0
3 years ago
You testify as an expert witness in a case involving an accident in which car A slid into the rear of car B, which was stopped a
AfilCa [17]

Answer:

Explanation:

a Downward acceleration of car A along the slope

= g sinθ - μ g cosθ

= g ( sinθ - μ  cosθ)

= 9.8 ( sin 12 - .6 x cos 12 )

= 9.8 x ( .2079 - .5869 )

= - 3.714 m / s²

So there will be deceleration

v² = u² - 2 a s

= 18² - 2 x 3.714 x 24

= 324 - 178

= 146

v = 12 .08 m /s

b )

In the second case , kinetic friction changes

downward acceleration

= g ( sinθ - μ  cosθ)

= 9.8 ( sin12 - .1 x cos 12 )

9.8 ( .2079  -  .0978 )

= 1.079 m /s

there will be reduced acceleration

v² = u² - 2 a s

= 18² +2 x1.079 x 24

= 324 + 52

= 376

v = 19.4  m /s

7 0
3 years ago
Which of the following is in correct chronological order?
tankabanditka [31]

Answer:

Hey there

I will give you the correct answer based on Wikipedia timelines.

You are correct (Copernicus, Brahe, Kepler, Newton)

Nicolaus Copernicus: 19 February 1473 – 24 May 1543.

Tyco Brahe: 14 December 1546 – 24 October 1601.

Johannes Kepler: 27 December 1571 – 15 November 1630.

I

Issac Newton: 4 January 1643 – 31 March 1727.

Brainly is GREATLY appreciated. it took me 30 minutes to get all the timelines!!!

4 0
3 years ago
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