3 years ago

Please helpppp. It's due in an hour

Mathematics

1 answer:

TEA [102]3 years ago

4 0

Answer:

sowwy

Step-by-step explanation:

i can't help WITH MY SMALL BRAIN

You might be interested in

(Label each one)

shutvik [7]

1,3) no solution

2,4,5,6,7) solution

5 0

4 years ago

I need the answer to this question.

Sidana [21]

I think it's 11 bc idk lol

3 0

3 years ago

Previous studies have reported that elite athletes are often deficient in their nutritional intake (for example, total calories,

Naddik [55]

Answer:

(3138.29, 3705.11)

Step-by-step explanation:

Given that for sample size of n = 50 male athletes from eight Canadian sport centers surveyed, the average caloric intake was 3077.0 kilocalories/day with a sample standard deviation of 987.0.

The recommended amount = 3421.70

To construct 95% confidence interval

Since population std deviation is not known we use t critical value for degree of freedom 50-1 =49

t critical = 2.010

Hence margin of error = $2.010*\frac{987}{\sqrt{50-1} } \\=283.41$

Confidence interval lower bound = $3421.70-283.41\\=3138.29$

Confidence interval upper bound = $3421.70+283.41\\=3705.11$

Conf interval = $(3138.29, 3705.11)$

7 0

4 years ago

Write 1 1/3 as an imprpoer fraction

harkovskaia [24]

1 is 3/3. 3/3 + 1/3 = 4/3.

5 0

4 years ago

Help me simplify these both PLEASE

sleet_krkn [62]

15.) 12a^11y^12/4a^5y^8
=12a^6y^4/4
=3a^6, y^4

16.)(2p^10z)^3
=8p^30 z^3

Your welcome love! :)

7 0

3 years ago