Answer:
it is not correct I have an answer for ''why''
Explanation:
You need to balance it
s= 2
0=2
S+30•2 --------> SO•3
2 2 2 2
S +3O•2-------->SO•2......MULTIPLY
2 4 2 4......LCM IS 4
2 1 2 1....DIVIDE BY 4
SO NOW WE GOT THE BALANCE NO. WE CAN PUT IT IN THE EQUATIONS.
2S+3O•2 -----> 2SO•3
now you can check the both sides its balances the correct answer is this
Answer:
Explanation:
At STP 1 mole of an ideal gas = 22.4 L.
Assuming SO2 (sulfur dioxide) acts as an ideal as, we have 16 g SO2 x 1 mol/64 g = 0.25 moles SO2
0.25 moles x 22.4 L/mole = 5.6 liters
Answer:
0.15 M KCl
Explanation:
(Step 1)
Convert the original volume from mL to L. Calculate the moles of the original solution.
75.0 mL / 1,000 = 0.0750 L
Molarity = moles / volume (L)
0.200 M = moles / 0.0750 L
0.0150 = moles
(Step 2)
Convert the final volume from mL to L. Calculate the final molarity.
100. mL / 1,000 = 0.100 L
Molarity = moles / volume (L)
Molarity = 0.0150 moles / 0.100 L
Molarity = 0.15 M
Answer:
No, because Flourine can only form 1 bond, thus backbonding is not obtainable
Answer: A
Explanation:
In both equations 2 things make one product