Answer:
Explanation:
Hello,
In this since one mole equals 6.022x10²³ particles of silver by means of the Avogadro's number, we can compute the moles in 4.27x10²² particles as shown below:
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How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH 4NO 3 in order to prepare a 0.452 m solution?
1 answer:
Answer:
0.768 kg
Explanation:
Step 1: Given data
- Mass of ammonium nitrate (solute): 27.8 g
- Molality of the solution (m): 0.452 m
Step 2: Calculate the moles corresponding to 27.8 g of ammonium nitrate
The molar mass of ammonium nitrate is 80.04 g/mol.
Step 3: Calculate the mass of water
The molality is equal to the moles of solute divided by the kilograms of solvent (water).
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Answer:
<h2>mass = 10.72 g</h2>Explanation:
Density of a substance can be found by using the formula
Making mass the subject we have
From the question
Density = 2.70 g/cm³
We assume that the aluminum is a cuboid
and volume of a cuboid is given by
Volume = length × width × height
length = 5.3 cm
width = 0.32 cm
height = 2.34 cm
Volume = 5.3 × 0.32 × 2.34 = 3.97 cm³
Substitute the values into the above and solve for the mass
We have
mass = 2.70 × 3.97
We have the final answer as
<h3>mass = 10.72 g</h3>Hope this helps you
Answer:
The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is .
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 104 kPa
= final pressure of gas = 52 kPa
= initial volume of gas =
= final volume of gas = ?
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
The volume of air at where the pressure and temperature are 52 kPa, -5.0 ºC is .