How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH 4NO 3 in order to prepare a 0.452 m solution?
1 answer:
Answer:
0.768 kg
Explanation:
Step 1: Given data
- Mass of ammonium nitrate (solute): 27.8 g
- Molality of the solution (m): 0.452 m
Step 2: Calculate the moles corresponding to 27.8 g of ammonium nitrate
The molar mass of ammonium nitrate is 80.04 g/mol.
Step 3: Calculate the mass of water
The molality is equal to the moles of solute divided by the kilograms of solvent (water).
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