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Nesterboy [21]
3 years ago
11

HELP Consider this equation...

Chemistry
2 answers:
noname [10]3 years ago
6 0
Not correct


Hope that kinda helped
Mashcka [7]3 years ago
4 0

Answer:

it is not correct I have an answer for ''why''

Explanation:

You need to balance it

s= 2

0=2

S+30•2 --------> SO•3

2 2 2 2

S +3O•2-------->SO•2......MULTIPLY

2 4 2 4......LCM IS 4

2 1 2 1....DIVIDE BY 4

SO NOW WE GOT THE BALANCE NO. WE CAN PUT IT IN THE EQUATIONS.

2S+3O•2 -----> 2SO•3

now you can check the both sides its balances the correct answer is this

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Calcium and water form calcium hydroxide and hydrogen gas also called what type of reaction
Gekata [30.6K]
Reaction of calcium with water
Calcium reacts slowly with water. This is in contrast with magnesium, immediately above calcium in the periodic table, which is virtually unreactive with cold water. The reaction forms calcium hydroxide, Ca(OH)2 and hydrogen gas (H2).
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3 years ago
In cells,____ are proteins that are needed to lower the amount of energy required to start chemical reactions.
Arturiano [62]

Answer:

Enzymes

Explanation:

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7 0
3 years ago
Read 2 more answers
Determine the molar mass of Ze(NO3)2. (Ze=55.85 N=14.01 O=16.00) *<br> Help
Arturiano [62]

Answer:

179.87 g/mol

Explanation:

First you need to determine the number of each elements in the molecule.  This information comes from the molecular formula.  

Ze(NO3)2 tells us that there is 1 Ze atom and 2 NO3 anions per molecule.  each NO3 anion will have 1 nitrogen and 3 oxygens.  Due to that, one molecule of Ze(NO3)2 will have 1 atom of Ze, 2 atoms of nitrogen (N), and 6 atoms of oxygen (O).

Next you need to add all of the individual atom's molar masses to get the over all molar masses.  The molar masses of each element is in the question but it can also be found on the periodic table.

molar mass of Ze(NO3)2 = 55.85g/mol + (14.01g/mol*2) + (16.00g/mol*6)

molar mass of Ze(NO3)2 = 179.87 g/mol

I hope this helps.

5 0
3 years ago
Which tool was most likely used in a procedure if the lab report shows that approximately 300 mL of water was used?
BARSIC [14]

Answer:

A beaker

Explanation:

8 0
3 years ago
2. (2 pts) How would you prepare 1.5 liters of 2 M KCI (MW=74.55 g/mol)
ra1l [238]

Answer:

Dissolve 226 g of KCl in enough water to make 1.5 L of solution

Explanation:

1. Calculate the moles of KCl needed

n = \text{1.5 L} \times \dfrac{\text{2 mol}}{\text{1 L}}= \text{3.0 mol}

2. Calculate the mass of KCl

m = \text{3.0 mol} \times \dfrac{\text{74.55 g}}{\text{1 mol}}= \text{224 g}

3. Prepare the solution

  • Measure out 224 g of KCl.
  • Dissolve the KCl in a few hundred millilitres of distilled water.
  • Add enough water to make 1.5 L of solution. Mix thoroughly to get a uniform solution.
8 0
3 years ago
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