HELP PLS MARKING BRANLIST TAKING TEST RN

Calculate the number of atoms contained in a cylinder (1 m radiusand1 m deep)of (a) magnesium (b) lead.

Jobisdone [24]

Answer:

The question is incomplete,below is the complete question

"Calculate the number of atoms contained in a cylinder (1μm radius and 1μm deep)of (a) magnesium (b) lead."

Answer:

a. 1.35*10^{11} atoms

b. 1.03*10^{11} atoms

Explanation:

First, we determine the volume of the magnesium in the cylinder container

using the volume of a cylinder

$V=\pi r^{2}h\\ r=10^{-6}m\\ h=10^{-6}m\\V=\pi *10^{-6*2}*10^{-6}\\V=\pi *10^{-18}\\V=3.14*10^{-18}m^{3}\\$

a. Next we determine the mass of the magnesium ,

using the density=mass/volume

since density of a magnesium

$the density of magnesium =1.738*10^{3}kg/m^{3} \\mass=density * volume \\mass=1.738*10^{3}*3.14*10^{-18}\\mass=5.46*10^{-15}kg\\ \\mass=5.46*10^{-12}g\\$

Finally to calculate the number of atoms,

we determine the number of moles

mole=mass/molarmass

$mole=5.46*10^{-12}/ 24.305\\mole=0.225*10^{-12}mol\\$

Hence the number of atoms is

number of atoms=mole*Avogadro's constant

$number of atoms = 0.225*10^{-12}*6.02*10^{23}\\number of atoms =1.35*10^{11} atoms$

b. for he lead, we determine the mass of the lead ,

using the density=mass/volume

since density of a magnesium

$the density of lead =11.34*10^{3}kg/m^{3} \\mass=density * volume \\mass=11.34*10^{3}*3.14*10^{-18}\\mass=35.60*10^{-15}kg\\ \\mass=35.60*10^{-12}g\\$

Finally to calculate the number of atoms,

we determine the number of moles

mole=mass/molarmass

$mole=35.60*10^{-12}/ 207.2\\mole=0.1718*10^{-12}mol\\$

Hence the number of atoms is

number of atoms=mole*Avogadro's constant

$number of atoms = 0.1718*10^{-12}*6.02*10^{23}\\number of atoms =1.03*10^{11} atoms$

3 0

3 years ago

A sample of a gas is expanded to twice its original volume while its temperature is held constant. Relative to their original av

aleksley [76]

Answer:

Lesser as it drops based on increase in volume

Explanation:

Kinetic Energy is directly proportional to temperature. so since the temperature is held constant and volume increased, Temperature would drop and kinetic energy would reduce

4 0

4 years ago

A box of mass 50 kg is at rest on a horizontal frictionless surface. A constant horizontal force F then acts on the box

tia_tia [17]

Answer: F = 59 N

Explanation:

F = ma

a = F/m

s = ½at²

a = 2s/t²

F/m = 2s/t²

F = 2sm/t²

F = 2(28)(50) / 6.9²

F = 58.811... ≈ 59 N

3 0

3 years ago

What is the speed of light?

disa [49]

Answer:

299792458 meters per second (approximately 300000 km/s or 186000 mi/s)

Explanation:

The speed of light in vacuum, commonly denoted c, is a universal physical constant that is important in many areas of physics. Its exact value is defined as 299792458 meters per second (approximately 300000 km/s or 186000 mi/s).[Note 3] According to the special theory of relativity, c is the upper limit for the speed at which conventional matter, energy or any signal carrying information can travel through space.

6 0

2 years ago

Read 2 more answers

A block-spring system oscillates with an amplitude of 3.55 cm. the spring constant is 250 n/m and the mass of the block is 0.800

liraira [26]

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]$

6 0

4 years ago