In stars more massive than the sun, the core temperature is hotter, which allows for fusion of more complex elements.
Most of the fusion occurs in the core.
In stars more massive than the sun, fusion continues through Deuterium, Carbon, and finally reaching iron/nickel.
Up to this point, the fusion reaction was endothermic, which means that the energy expended to produce the fusion reaction was exceeded by the energy produced in the reaction.
Fusion past iron is exothermic, and therefore the star will be able to survive by fusing elements heavier than iron.
After the core is almost entirely iron, the star is no longer in the Main Sequence.
So, fusion in stars more massive than the sun continue fusing until the core is almost entirely <em>iron</em>.
Air pressure is the wi get of air molecules pressing down on the earth. The pressure of the air molecules changes as you move upward from sea level into the atmosphere, the highest pressure is at sea level where the density of the air molecules is the greatest.
Answer:
0.247 μC
Explanation:
As both sphere will be at the same level at wquilibrium, the direction of the electric force will be on the x axis. As you can see in the picture below, the x component of the tension of the string of any of the spheres should be equal to the electric force of repulsion. And its y component will be equal to the weight of one sphere. We can use trigonometry to find the components of the tensions:
![F_y: T_y - W = 0\\T_y = m*g = 0.002 kg *9.81m/s^2 = 0.01962 N](https://tex.z-dn.net/?f=F_y%3A%20%20T_y%20-%20W%20%3D%200%5C%5CT_y%20%3D%20m%2Ag%20%3D%200.002%20kg%20%2A9.81m%2Fs%5E2%20%3D%200.01962%20N)
![T_y = T_*cos(50)\\T = \frac{T_y}{cos(50)} = 0.0305 N](https://tex.z-dn.net/?f=T_y%20%3D%20T_%2Acos%2850%29%5C%5CT%20%3D%20%5Cfrac%7BT_y%7D%7Bcos%2850%29%7D%20%3D%200.0305%20N)
![T_x = T*sin(50) = 0.0234 N](https://tex.z-dn.net/?f=T_x%20%3D%20T%2Asin%2850%29%20%3D%200.0234%20N)
The electric force is given by the expression:
![F = k*\frac{q_1*q_2}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20k%2A%5Cfrac%7Bq_1%2Aq_2%7D%7Br%5E2%7D)
In equilibrium, the distance between the spheres will be equal to 2 times the length of the string times sin(50):
![r = 2*L*sin(50) = 2 * 0.1m * sin(50) 0.1532 m](https://tex.z-dn.net/?f=r%20%3D%202%2AL%2Asin%2850%29%20%3D%202%20%2A%200.1m%20%2A%20sin%2850%29%200.1532%20m)
And k is the coulomb constan equal to 9 *10^9 N*m^2/C^2. q1 y q2 is the charge of each particle, in this case, they are equal.
![F_x = T_x - F_e = 0\\T_x = F_e = k*\frac{q^2}{r^2}](https://tex.z-dn.net/?f=F_x%20%3D%20T_x%20-%20F_e%20%3D%200%5C%5CT_x%20%3D%20F_e%20%3D%20k%2A%5Cfrac%7Bq%5E2%7D%7Br%5E2%7D)
![q = \sqrt{T_x *\frac{r^2}{k}} = \sqrt{0.0234 N * \frac{(0.1532m)^2}{9*10^9 N*m^2/C^2} } = 2.4704 * 10^-7 C](https://tex.z-dn.net/?f=q%20%3D%20%5Csqrt%7BT_x%20%2A%5Cfrac%7Br%5E2%7D%7Bk%7D%7D%20%3D%20%5Csqrt%7B0.0234%20N%20%2A%20%5Cfrac%7B%280.1532m%29%5E2%7D%7B9%2A10%5E9%20N%2Am%5E2%2FC%5E2%7D%20%7D%20%3D%202.4704%20%2A%2010%5E-7%20C)
O 0.247 μC
Answer:
The difference between ice and steam in Celsius (Centigrade) is 100 deg.
So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.
So 8 cm is 4 cm greater than the ice point
4 cm / 20 cm = 1/5 since the steam point and the ice point are 20 cm apart
Then 1/5 * 100 deg C = 20 deg C the requested temperature
Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.Displacement<span> is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
</span>To calculate displacement<span>, simply draw a vector from your starting point to your final position and solve for the length of this line. If your starting and ending position are the same, like your circular 5K route, then your </span>displacement<span> is 0. In physics, </span>displacement<span> is represented by Δs.
For me to solve this I would need to know the time, but I can give you a handy displacement calculator I used that helped me.
https://www.easycalculation.com/physics/classical-physics/constant-acc-displacement.php
Hope I helped.
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