If there is a 25 [lbs] of force acting on a 5 [lbs] of mass, what is the acceleration of that mass?
1 answer:
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Answer:
The value is
Explanation:
From the question we are told that
The mass of the object is
The unstressed length of the string is
The length of the spring when it is at equilibrium is
The initial speed (maximum speed)of the spring when given a downward blow
Generally the maximum speed of the spring is mathematically represented as
Here A is maximum height above the floor (i.e the maximum amplitude)
and is the angular frequency which is mathematically represented as
So
=>
Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as
=>
=>
Generally at equilibrium position the net force acting on the spring is
=>
=>
So
=>
Answer:
Answer:
a. t = 1.43 s
b. d = 7.88 m
Explanation:
a. The time of flight can be found using the following equation:
Where:
: is the final height = -10 m
: is the initial height = 0
: is the initial speed in the vertical direction = 0
g: is the acceleration due to gravity = 9.81 m/s²
By solving the above equation for "t" we have:
Hence, the ball will hit the ground in 1.43 s.
b. The distance in the horizontal direction can be found as follows:
Where:
x₀: is the initial position in the horizontal direction = 0
a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)
Therefore, the ball will travel 7.88 m before it hits the ground.
I hope it helps you!