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3 years ago

Simplify 23.85 / o.15

Mathematics

1 answer:

Licemer1 [7]3 years ago

8 0

The answer to this problem is 23.85/0.15 =159 Hope I helped!

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Which value represents the dimensions, in centimeters, of a rectangle prism?

slamgirl [31]

Length*width*height=volume of rectangular prism

7 0

3 years ago

A type of bacteria has a very high exponential growth rate of 80% every hour. If there are 10 bacteria, determine how many will

Lana71 [14]

<h3>There are 189 bacteria in 5 hours</h3><h3>There are 13382588 bacteria in 1 day</h3><h3>There are $10(1.8)^{168}$ bacteria in 1 week</h3>

<em><u>Solution:</u></em>

Given that,

A type of bacteria has a very high exponential growth rate of 80% every hour

There are 10 bacteria

<em><u>The increasing function is given as:</u></em>

$y = a(1+r)^t$

Where,

y is future value

a is initial value

r is growth rate

t is time period

From given,

a = 10

$r = 80 \5 = \frac{80}{100} = 0.8$

<em><u>Determine how many will be in 5 hours</u></em>

Substitute t = 5

$y = 10(1 + 0.8)^5\\\\y = 10(1.8)^5\\\\y = 10 \times 18.89568\\\\y \approx 188.96$

y = 189

Thus, there are 189 bacteria in 5 hours

<em><u>Determine how many will be in 1 day ?</u></em>

1 day = 24 hours

Substitute t = 24

$y = 10(1 + 0.8)^{24}\\\\y = 10(1.8)^{24}\\\\y = 10 \times 1338258.84\\\\y = 13382588.45\\\\y \approx 13382588$

Thus, there are 13382588 bacteria in 1 day

<em><u>Determine how many will be in 1 week</u></em>

1 week = 168

Substitute t = 168

$y = 10(1 + 0.8)^{168}\\\\y = 10(1.8)^{168}$

Thus there are $10(1.8)^{168}$ bacteria in 1 week

6 0

3 years ago

7,696 divided by 52 p

Fittoniya [83]

148 is the answer...

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3 years ago

What is (f−g)(x)<br> (f−g)(x)=

quester [9]

Answer:

3x^5 -2x^4 -x^2 +x -21

Step-by-step explanation:

We need to subtract g(x) from f(x)

f(x) = 3x^5 +6x^2 -5

g(x) = 2x^4 +7x^2 -x+16

f(x) -g(x) = 3x^5 +6x^2 -5 - (2x^4 +7x^2 -x+16)

Distribute the minus sign

3x^5 +6x^2 -5 - 2x^4 -7x^2 +x-16

I like to line them up vertically

3x^5 +6x^2 -5

- 2x^4 -7x^2 +x-16

---------------------------------------

3x^5 -2x^4 -x^2 +x -21

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3 years ago

What is the vertex form of the quadratic equation represented on the table?

sergeinik [125]

Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}$

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2 years ago