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Dmitry [639]
3 years ago
6

How to simplify 7m-2m

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0
The answer is 5m because you just have to do 7-5.You don't need to careabout the.Just add the m at the end.
vichka [17]3 years ago
3 0
You would have no problem at all if it said "7 cows minus 2 cows", or "7 books minus 2 books". The THINGS just happen to be m's instead of cows or books.
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The sum of three times a and four is the same as five yimes a?
Umnica [9.8K]

\text{the sum of three times a and four}:3a+4\\\\\text{five times a}:5a\\\\The\ equation:\\\\3a+4=5a\qquad\text{subtract 3a from both sides}\\\\4=2a\qquad\text{divide both sides by 2}\\\\2=a\to\boxed{a=2}

7 0
3 years ago
If the maker of the promissory note fails to pay the note on the due date,the note is said to be
Svetlanka [38]

Answer:

When the maker of a promissory note fails to pay, the note is said to be <u>dishonored.</u>

Step-by-step explanation:

5 0
2 years ago
To find 19+(11+37) Lenny added 19 and 11. Then he added 37 to the sum .which property did he use
Alika [10]
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8 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 &lt; T &lt; 36 , where T is
antoniya [11.8K]

Answer:

N(T(t)) = 1408t^2 - 385.6t - 105.52

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

N(T(t)) = 22 * (8t + 1.7)^2  - 123 * (8t + 1.7) + 40

N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40

N(T(t)) = 1408t^2 + 598.4t + 63.58 -  984t - 169.1

N(T(t)) = 1408t^2 - 385.6t - 105.52

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

8019 = 1408t^2 - 385.6t - 105.52

1408t^2 - 385.6t - 8124.52 = 0

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

4 0
3 years ago
Solve using factoring
irina1246 [14]

Answer: you can use Photomath


Step-by-step explanation:


4 0
3 years ago
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