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Serhud [2]
3 years ago
9

HELP ASAP

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
6 0
Imposter is sus (okay i’m sorry i just want points for my test or i’ll fail)
STALIN [3.7K]3 years ago
4 0

Answer and Step-by-step explanation:

First, you would subtract \frac{1}{2} (or 0.5) to both sides.

\frac{1}{x} = 1.5

Now multiply x to both sides, then divide both sides by 1.5.

\frac{2}{3}  = x

<u>Two thirds is equal to x.</u>

<u><em>I hope this helps!</em></u>

<u><em></em></u>

<u><em>#teamtrees #WAP (Water And Plant)</em></u>

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Answer:

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Lower = \mu - 2\sigma = 373- 2(67) = 239

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

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