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Serhud [2]
3 years ago
9

HELP ASAP

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
6 0
Imposter is sus (okay i’m sorry i just want points for my test or i’ll fail)
STALIN [3.7K]3 years ago
4 0

Answer and Step-by-step explanation:

First, you would subtract \frac{1}{2} (or 0.5) to both sides.

\frac{1}{x} = 1.5

Now multiply x to both sides, then divide both sides by 1.5.

\frac{2}{3}  = x

<u>Two thirds is equal to x.</u>

<u><em>I hope this helps!</em></u>

<u><em></em></u>

<u><em>#teamtrees #WAP (Water And Plant)</em></u>

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Find the value of the variable and YZ if Y is between X and Z
PIT_PIT [208]
If point Y is between points X and Z, then

XY + YZ = XZ

In words, the distance from X to Y, plus the distance from Y to Z, is equal to the distance from X to Z. (See the attached picture.)

So 6b + 8b = 175

Can you finish it?


8 0
3 years ago
Read 2 more answers
The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards
jonny [76]
H = 3b+2
A = (h*b)/2     28 = (3b+2)b/2     56 = 3b²+2b    0 = 3b² + 2b - 56

⊕\left \{ {{y=2} \atop {x=2}} \right.  \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \beta  \\  \\  \\  x^{2}  \sqrt{x}  \sqrt[n]{x}  \frac{x}{y}  x_{123}  x^{123}  \leq  \geq  \pi  \alpha   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x_{123}  \int\limits^a_b {x} \, dx  \left \{ {{y=2} \atop {x=2}}
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8 0
3 years ago
Please help picture shown
SashulF [63]
\dfrac{x}{x-5} ~ \cdot~ \dfrac{2x}{x+4} =\dfrac{x~ \cdot~ 2x}{(x-5)(x+4)}= \dfrac{2x^2}{x^2 -x -20}

The answer is D.

Hope it helps!
5 0
3 years ago
What is the simplified form of
umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

Step-by-step explanation:

Given the expression

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)

solving the expression

=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)

apply the rule: a^0=1,\:a\ne \:0

=-7+5x^2-x+6-\left(-8x^2+x+3\right)

=-7+5x^2-x+6+8x^2-x-3

simplify

=13x^2-2x-4

Therefore, the simplified form is:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0
3 years ago
Find the distance between the points (3, 8) and (0,4).
Bingel [31]

Answer:

5

Step-by-step explanation:

(3,8) (0,4)

X1 = 3    X2 = 0

Y1 = 8    Y2 = 4

D=\sqrt{(X1-X2)^{2}+ (Y1-Y2)^{2}  }

D= \sqrt{(3-0)^{2} + (8-4)^{2} }

Do what's in the parentheses so...

  1. 3-0= 3
  2. 8-4= 4

Now plug it in!

D= \sqrt{(3)^{2}+(4)^{2}  }

Now you are going to finish the parentheses so...

  1. (3)^2= 9
  2. (4)^2= 16

Plug that in so that you have this...

\sqrt{9+16}

Add 9+16 to get...

\sqrt{25}

Then you are going to find the number or numbers that make this a perfect square...

\sqrt{25}= 5

So 5 is your answer

7 0
3 years ago
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