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Irina-Kira [14]
3 years ago
10

How many moles of copper Il sulfide can be produced from 2.8 moles of sulfur? Cu + S --> CuS​

Chemistry
1 answer:
Kamila [148]3 years ago
5 0

Answer: 2.8 moles of copper (Il) sulfide (CuS) will be produced from 2.8 moles of sulphur.

Explanation:

The balanced chemical reaction is:

Cu+S\rightarrow CuS  

According to stoichiometry :

1 mole of S produce =  1 mole of copper (Il) sulfide (CuS)

Thus 2.8 moles of S will produce=\frac{1}{1}\times 2.8=2.8moles of copper (Il) sulfide (CuS)

Thus 2.8 moles of copper (Il) sulfide (CuS) will be produced from 2.8 moles of sulphur.

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An electron's positional potential energy while in a given principle quantum energy level is given by Eₙ = - A/n² and A = constant = 2.18 x 10⁻¹⁸j. So to remove an electron from the valence level of Boron (₅B), energy need be added to promote the electron from n = 2 to n = ∞. That is, ΔE(ionization) = E(n=∞) - E(n=2) = (-A/(∞)²) - (-A/(2)²) = [2.18 x 10⁻¹⁸j/4] joules = 5.45 x 10⁻¹⁹ joules.

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