Question

88.5 mol of P4O10 contains how many moles of P?

Answer 1

Answer : The number of moles of phosphorous are 354 moles.

Explanation :

The formula of given compound is, $P_4O_{10}$

In $P_4O_{10}$ compound, there 4 moles of phosphorus and 10 moles of oxygen.

As we are given that the moles of $P_4O_{10}$ is 88.5 mole. Now we have to determine the number of moles of phosphorous (P).

As, 1 mole of $P_4O_{10}$ has 4 moles of phosphorous

So, 88.5 mole of $P_4O_{10}$ has $4\times 88.5=354moles$ of phosphorous

Therefore, the number of moles of phosphorous are 354 moles.

Answer 2

This problem can be solved directly using stoichiometry. We can actually see that for every mol of P4O10, there are 4 moles of P. Therefore the total moles of P is:

moles P = 88.5 moles P4O10 * (4 moles P / 1 mole P4O10)

moles P = 354 moles P