The formula of acetic acid is CH3COOH => C2H4O2.
So, the acetic acid has the same number of atoms of carbon (C) than of oxygen (O).
Therefore, the sample that contains 96.5 moles of carbon, will contain also 96.5 moles of O.
Answer: 96.5 moles of oxygen.
This is an exercise in<u> the General Combined Gas Law</u>.
To start solving this exercise, we obtain the following data:
<h3>
Data:</h3>
- V₁ = 4.00 l
- P₁ = 365 mmHg
- T₁ = 20 °C + 273 = 293 K
- V₂ = 2,80 l
- T₂ = 30 °C + 273 = 303 K
- P₂ = ¿?
We apply the following formula:
- P₁V₁T₂=P₂V₂T₁ ⇒ General formula
Where:
- P₁=Initial pressure
- V₁=Initial volume
- T₂=end temperature
- P₂=end pressure
- T₂=end temperature
- V₁=Initial temperature
We clear for final pressure (P2)

We substitute our data into the formula:



Answer: The new canister pressure is 539.224 mmHg.
<h2>{ Pisces04 }</h2>
Answer:
6NO2+3H2O-------->3HNO2+3HNO3