Question

Calculate the de Broglie wavelength of a shotgun

Answer 1

Answer : The de Broglie wavelength will be $3.68\times 10^{-33}m$

Solution :

The formula used for de Broglie wavelength is:

$\lambda=\frac{h}{mv}$ ..........(1)

where,

$\lambda$ = wavelength  = ?

h = Planck's constant  = $6.626\times 10^{-34}Js$

m = mass  = 1.2 g = 0.0012 kg

Conversion used : 1 kg = 1000 g

v = velocity  = 150 m/s

Now put all the given values in equation 1, we get:

$\lambda=\frac{6.626\times 10^{-34}Js}{(0.0012kg)\times (150m/s)}$

$\lambda=3.68\times 10^{-33}m$

Therefore, the de Broglie wavelength will be $3.68\times 10^{-33}m$