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givi [52]
3 years ago
13

Student uses a magnet to move 0.0 25 KG metal box the magnet exerts a force of 5N which causes the ball to begin moving what is

the acceleration of the ball when it begins to move
Chemistry
1 answer:
daser333 [38]3 years ago
3 0

Answer: 200 m/s2

Explanation:

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What is water's density at 93 ∘C? Assume a constant coefficient of volume expansion. Express your answer with the appropriate un
Ganezh [65]

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

3 0
3 years ago
Which of the following is not a clue that a chemical reaction has taken place? *
DaniilM [7]

Answer:

A pure solid is heated and turns into a pure liquid.

Explanation:

No colour change recorded, only change of state, hence this is a physical change - physical changes I.e. change of state and temperature are not chemical reactions.

7 0
3 years ago
What are the properties of salt
GrogVix [38]
The compound is sodium chloride 
6 0
3 years ago
Read 2 more answers
What is the molality of a solution of water and kcl if the freezing point of the solution is –3mc030-1.jpgc?
Natasha_Volkova [10]
We will use the expression for freezing point depression ∆Tf
     ∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is 
     ∆Tf = 0C - (-3°C) = 3°C 
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and  one Cl- ion:
     KCl → K+ + Cl- 
Therefore, the molality m of the solution can be calculated as 
     3 = 2 * 1.86 * m
     m = 3 / (2 * 1.86)
     m = 0.80 molal
4 0
3 years ago
How many liters of radon gas would be in 3.43 moles at standard temperature and pressure (273 K and 100 kPa)?
MissTica

Answer: Option B. 76.83L

Explanation:

1 mole of a gas occupy 22.4L at stp. This implies that 1mole of Radon also occupy 22.4L at stp.

If 1 mole of Radon = 22.4L

Therefore, 3.43 moles of Radon = 3.43 x 22.4 = 76.83L

5 0
3 years ago
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