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3 years ago

(D.) Define the following Moment (.) Moment of a force (.) couple of force (.) torque

Physics

1 answer:

erik [133]3 years ago

4 0

Moment of force. Hope this helped

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Approximately 80% of the energy used by the body must be dissipated thermally. The mechanisms available to eliminate this energy

Semenov [28]

Answer:

the correct answer is c) 23 g

Explanation:

The heat lost by the runner has two parts: the heat absorbed by sweat in evaporation and the heat given off by the body

Q_lost = - Q_absorbed

The latent heat is

Q_absorbed = m L

The heat given by the body

Q_lost = M $c_{e}$ ΔT

where m is the mass of sweat and M is the mass of the body

m L = M c_{e} ΔT

m = M c_{e} ΔT / L

let's replace

m = 90 3.500 1.8 / 2.42 10⁶

m = 0.2343 kg

reduced to grams

m = 0.2342 kg (1000g / 1kg)

m = 23.42 g

the correct answer is c) 23 g

8 0

3 years ago

What's a refractive medium that focuses light to a single point?

ss7ja [257]

Answer:

The convex lens is shaped so that all light rays that enter it parallel to its axis cross one another at a single point on the opposite side of the lens.

Explanation:

3 0

3 years ago

WHAT HAPPENS TO THE VELOCITY AND ACCELERATION OF A BODY FALLING FREELY IN A VACUUM?

mixas84 [53]

both remains constant

..........

7 0

3 years ago

A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 cm^2, stands on the floor.An elephant weighing 20

Klio2033 [76]

Answer:

$\boxed{{\boxed{\blue{ 12.5}}}}$

Explanation:

Given, for girl : Weight or force;

$\rm \: F_1 = 50 \: kgf$

Area of both heels;

$\rm \: A_1 = \; 2 ×1 \; cm^2 = 2 \: cm^2$

$\rm \: Pressure \: P_1 = \cfrac{F_1}{ A_1 } = \dfrac{50 \: kgf}{2 \: cm {}^{2} } = 25 \: kgf \: cm {}^{ - 1}$

For elephant, Weight = Force $\rm F_2$ = 2000 kg•f

Area of 4 feet;

$\rm \: A_2 = \; 4 \times 250 \; cm^2 = 1000 \: cm^2$

$\rm \: Pressure \: P_2 = {F_2}/{A_2} \; = \cfrac{2 \cancel{0 00 }\: kgf}{1 \cancel{000} \: cm^2} = 2 \: kgf \: { \:cm}^{- 1}$

Now;

$\rm = \dfrac{Pressure \: Exerted \: by \: the \: Girl}{Pressure \: exerted \: by \: the \: elephant}$

$= \rm \: P_1/P_2$

$\implies \rm\cfrac{25 \: kgf \: \: cm {}^{ - 2} }{2 \: kgf \: cm {}^{ - 2} } = \rm\cfrac{25 \: \cancel{kgf \: \: cm {}^{ - 2}} }{2 \: \cancel{ kgf \: cm {}^{ - 2}} } = \boxed{12.5}$

Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.

I aspire this helps!

3 0

2 years ago

How do motion and Newton's laws apply to your everyday life?

Marina86 [1]

When you jumó ur legs put force on ground

6 0

2 years ago

(D.) Define the following Moment (.) Moment of a force (.) couple of force (.) torque​

(D.) Define the following Moment (.) Moment of a force (.) couple of force (.) torque