Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. The electric field at a po
1 answer:
Answer:
E = 0 r <R₁
Explanation:
If we use Gauss's law
Ф = ∫ E. dA = / ε₀
in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.
Consequently by Gauss's law the electric field is ZERO
E = 0 r <R₁
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Answer:
44.09 pounds
Explanation:
We got that 20 % of the mass of a nutty chocolate bar its pecans, if 4.0 kg of pecans were used, we need to find the X in the equation
where X its the total mass of nutty chocolate bars produced. So, we can just divide by 0.2 on both sides, and we find:
Of course, we need the total mass produced in pounds, and not in kilograms. Looking at an conversion table, we can find that 1 kg its 2.20462 pounds, multiplying the value for total mass produced by the conversion factor we get:
Now, we just need to round off to two significant figures. This is:
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the total mass of nutty chocolate bars made last Tuesday to two significant figures.