Answer:
(a) ![fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b) [tex]r=26.008\ cm](https://tex.z-dn.net/?f=fd%3D1.7058%5Ctimes%2010%5E%7B-5%7D%5C%20L.hr%5E%7B-1%7D.cm%3C%2Fp%3E%3Cp%3E%28b%29%20%5Btex%5Dr%3D26.008%5C%20cm)
Explanation:
(a)
- Oxygen consumption rate of humans,

area of human skin, 
- diffusion rate through skin of humans,

- ∴


<u>Flux of diffusion rate, </u>


![fd=1.7058\times 10^{-5}\ L.hr^{-1}.cm(b)Surface area for a spherical animal:[tex]A=4.\pi.r^2](https://tex.z-dn.net/?f=fd%3D1.7058%5Ctimes%2010%5E%7B-5%7D%5C%20L.hr%5E%7B-1%7D.cm%3C%2Fp%3E%3Cp%3E%28b%29%3C%2Fp%3E%3Cp%3ESurface%20area%20for%20a%20spherical%20animal%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DA%3D4.%5Cpi.r%5E2)
Diffusion flux rate for animal:



It is stable if the atom has a full outer shell
Answer:
option A
Explanation:
Given,
wavelength of light,
refractive index of gasoline, n₁ = 1.40
Refractive index of water, n₂ = 1.33
thickness of the film, t = ?
Condition of constructive interference is given by

For minimum thickness of the film m = 0
From the question we can clearly observe that phase change from gasoline to air
so, n = 1.4


Hence, the correct answer is option A
Answer:
a = 0.5 m/s²
Explanation:
Applying the definition of angular acceleration, as the rate of change of the angular acceleration, and as the seats begin from rest, we can get the value of the angular acceleration, as follows:
ωf = ω₀ + α*t
⇒ ωf = α*t ⇒ α =
= 
The angular velocity, and the linear speed, are related by the following expression:
v = ω*r
Applying the definition of linear acceleration (tangential acceleration in this case) and angular acceleration, we can find a similar relationship between the tangential and angular acceleration, as follows:
a = α*r⇒ a = 0.067 rad/sec²*7.5 m = 0.5 m/s²
The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
<h3>WORK DONE:</h3>
The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;
Work done = force (F) × distance (m)
According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:
Work done = 30N × 0.5m
Work done = 15J
Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
Learn more about work done at: brainly.com/question/8119756?referrer=searchResults