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RUDIKE [14]
3 years ago
13

As it travels through a crystal, a light wave is described by the function E(x,t)=Acos[(1.57×107)x−(2.93×1015)t]. In this expres

sion, x is measured in meters and t is measured in seconds.
Part A
What is the speed of the light wave?
Express your answer to three significant figures and include appropriate units.
Physics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

Speed, v=1.86\times 10^8\ m/s

Explanation:

It is given that,

A light wave is described by the following function as :

E(x,t)=A\ cos[(1.57\times 10^7)x-(2.93\times 10^{15})t].....(1)

The general equation of wave is given by :

E=Acos(kx-\omega t)........(2)

On comparing equation (1) and (2)

k=(1.57\times 10^7)

\dfrac{2\pi}{\lambda}=(1.57\times 10^7)

\lambda=\dfrac{2\pi}{(1.57\times 10^7)}

Wavelength, \lambda=4.002\times 10^{-7}\ m

\omega=(2.93\times 10^{15})

\dfrac{2\pi}{T}=(2.93\times 10^{15})

\dfrac{1}{T}=\dfrac{(2.93\times 10^{15})}{2\pi}

Frequency, f=4.66\times 10^{14}\ Hz

Let v is the speed of the light wave. It is given by :

v=f\times \lambda

v=4.66\times 10^{14}\ Hz\times 4.002\times 10^{-7}\ m

v=1.86\times 10^8\ m/s

So, the speed of the light wave is 1.86\times 10^8\ m/s. Hence, this is the required solution.

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Answer:

The value  is   a =  2.7183

Explanation:

From the question we are told that

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  The  exponential relationship is  N  =  na^{kt}

Now from the given equation we have that

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So comparing this equation obtained an the given  exponential relationship we have that

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3 years ago
The tension in cable da has a magnitude of tda=6.27 lb. find the cartesian components of tension tda, which is directed from d t
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Complete Question

The Complete Question is attached below

We have that the Cartesian components of tension T_{da} is

T_{DA}=-4.433i-3.49j+2.735k

From the Question we are told that

M_{da}=6.27 lb\\\\w=9.50ft\\\\d=6.60ft\\\\h=4.50ft

\vec {DA}=-4.7i-3.7j+2.9k)ft

\vec {DB}=-1.9i-3.7j+1.9k)ft\\\\\vec {DC}=-1.9i+5.8j-1.6k)ft

Generally the equation for T_{DA}  is mathematically given as

T_{DA}=\phi_{DA}* M_{da}

Where

\phi_{DA}=\frac{-4.7i-3.7j+2.9k}{(-4.7)^2+(-3.7)^2+(2.9)^2}\\\\\phi_{DA}=\frac{-4.7i-3.7j+2.9k}{6.65}

Therefore

T_{DA}=\phi_{DA}* M_{da}

T_{DA}=\frac{-4.7i-3.7j+2.9k}{6.65}* 6.27

T_{DA}=-4.433i-3.49j+2.735k

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Answer:

Explanation:

From the given information:

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\mathbf{V_f =53.125 \times 10^4 \ m/s}

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