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slavikrds [6]
3 years ago
9

Atoms with atomic number ____ or less will not undergo fission.

Physics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
26

I hope its helped you a lot good luck
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If an object in motion, experiences a net zero unbalanced force, the the body
RSB [31]

Answer:

4) moves with constant velocity

Explanation:

If an object is in motion, three things can happen:

1. The object slows down in speed.

This means a net force is needed to be able to slow the object down in speed.

2. The object increases in speed.

This means a net force is needed to be able to increase the speed of the object.

3. The object remains in motion at the same speed.

No net zero unbalanced force is needed.

This is the given situation. So this is the right answer.

6 0
3 years ago
A single polarizer will stop _____ of the incoming light.
True [87]
A single polarizer will stop 50% of the incoming light.
8 0
3 years ago
Read 2 more answers
Two bar magnets are labeled A and B. The ends of each magnet are numbered 1 or 2, but the poles are not labeled. When A1 is brou
olga2289 [7]

The conclusion that is best supported by the data is;

D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.

3 0
3 years ago
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Earth rotates on its axis once every 24 hours, so that objects on its surface execute uniform circular motion about the axis wit
cestrela7 [59]

Answer:

v=1667.9km/h

a_{cp}=436.6km/h^2

Explanation:

The speed is the distance traveled divided by the time taken. The distance traveled in 24hs while standing on the equator is the circumference of the Earth C=2\pi R, where R=6371km is the radius of the Earth.

We have then:

v=\frac{C}{t}=\frac{2\pi R}{t}=\frac{2\pi (6371km)}{(24h)}=1667.9km/h

And then we use the centripetal acceleration formula:

a_{cp}=\frac{v^2}{R}=\frac{(1667.9km/h)^2}{(6371km)}=436.6km/h^2

6 0
3 years ago
Fighter jet starting from airbase A flies 300 km east , then 350 km at 30° west of north and then 150km north to arrive finally
Tems11 [23]
A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North. 
4 0
3 years ago
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