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Brut [27]
2 years ago
10

An element is highly conductive, highly reactive, soft, and lustrous. The element most likely belongs to which group?(1 point)

Physics
2 answers:
UkoKoshka [18]2 years ago
6 0

An element which is highly conductive, highly reactive, soft, and lustrous is most likely an alkali metal.

Alkali metals are in group 1 of the Periodic table which means that they have only a single valence electron.

This causes them to be soft and highly reactive because:

  • The single valance electron leads to weak bonds amongst the element's atoms which makes them soft
  • The elements want to lose the single valance electron so as to become stable so they will react with other elements to give away the electron.

Examples of alkali electrons include:

  • Lithium
  • Sodium
  • Potassium etc

In conclusion therefore, alkali metals are highly reactive and soft and so the element described above is most likely an alkali metal.

<em>Find out more at brainly.com/question/18722874.</em>

ryzh [129]2 years ago
3 0

Answer:

Alkali metals

Explanation:

Elements in this group are highly reactive, soft, lustrous and highly conductive.

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5 0
3 years ago
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A spaceship moves radially away from Earth with acceleration 29.4 m/s 2 (about 3g). How much time does it take for sodium street
Gemiola [76]

Answer:

doppler shift's formula for source and receiver moving away from each other:

<em>λ'=λ°√(1+β/1-β)</em>

Explanation:

acceleration of spaceship=α=29.4m/s²

wavelength of sodium lamp=λ°=589nm

as the spaceship is moving away from earth so wavelength of earth should increase w.r.t increasing speed until it vanishes at λ'=700nm

using doppler shift's formula:

<em>λ'=λ°√(1+β/1-β)</em>

putting the values:

700nm=589nm√(1+β/1-β)

after simplifying:

<em>β=0.17</em>

by this we can say that speed at that time is: v=0.17c

to calculate velocity at an acceleration of a=29.4m/s²

we suppose that spaceship started from rest so,

<em>v=v₀+at</em>

where v₀=0

so<em> v=at</em>

as we want to calculate t so:-

<em>t=v/a</em>                                                v=0.17c      ,c=3x10⁸           ,a=29.4m/s²

putting values:

=0.17(3x10⁸m/s)/29.4m/s²

<em>t=1.73x10⁶</em>

7 0
3 years ago
A private aviation helicopter's main rotor blades rotate at approximately
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Answer: 7.5 rev/s

Explanation:

We are given the angular velocity \omega a helicopter's main rotor blades:

\omega=450 rpm=450 \frac{rev}{min}

However, we are asked to express this \omega in the International Systrm (SI) units. In this sense, the SI unit for time is second (s):

\omega=450 \frac{rev}{min} \frac{1 min}{60 s}

\omega=7.5 \frac{rev}{s}

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3 years ago
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scoray [572]
In this question force is measured in  g cm/s2 so we know that to get the answer we times g by cm/s2 
50 × 20 = 1000
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3 years ago
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iris [78.8K]

Answer:

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