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Brut [27]
2 years ago
10

An element is highly conductive, highly reactive, soft, and lustrous. The element most likely belongs to which group?(1 point)

Physics
2 answers:
UkoKoshka [18]2 years ago
6 0

An element which is highly conductive, highly reactive, soft, and lustrous is most likely an alkali metal.

Alkali metals are in group 1 of the Periodic table which means that they have only a single valence electron.

This causes them to be soft and highly reactive because:

  • The single valance electron leads to weak bonds amongst the element's atoms which makes them soft
  • The elements want to lose the single valance electron so as to become stable so they will react with other elements to give away the electron.

Examples of alkali electrons include:

  • Lithium
  • Sodium
  • Potassium etc

In conclusion therefore, alkali metals are highly reactive and soft and so the element described above is most likely an alkali metal.

<em>Find out more at brainly.com/question/18722874.</em>

ryzh [129]2 years ago
3 0

Answer:

Alkali metals

Explanation:

Elements in this group are highly reactive, soft, lustrous and highly conductive.

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Answer:

(a). The speed of the ball after collision is 2.01 m/s.

(b). The speed of the block after collision 1.11 m/s.

Explanation:

Suppose, A steel ball of mass 0.500 kg is fastened to a cord that is 50.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal.

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Mass of steel block = 2.30 kg

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v=\sqrt{2gl}

Put the value into the formula

u=\sqrt{2\times9.8\times50.0\times10^{-2}}

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(a). We need to calculate the speed of the ball after collision

Using formula of collision

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Negative sign shows the opposite direction of initial direction.

(b). We need to calculate the speed of the block after collision

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v_{2}=(\dfrac{2m_{1}}{m_{1}+m_{2}})u_{1}+(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{2}

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v_{2}=(\dfrac{2\times0.5}{0.5+2.30})\times3.13+0

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(b). The speed of the block after collision 1.11 m/s.

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Answer:

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Explanation:

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    The mass is m =  0.350  \ kg

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The spring constant for this is mathematically represented as

       k  = \frac{F}{x}

Where F is the force on the spring which is mathematically evaluated as

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The period of oscillation is mathematically evaluated as

      T =  2 \pi \sqrt{\frac{m}{k} }

substituting values

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3 years ago
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Answer:

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now let's use the concept of density to calculate the mass of the system

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When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE

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3 years ago
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