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malfutka [58]
3 years ago
7

Answer the second question only please :D

Mathematics
2 answers:
irakobra [83]3 years ago
4 0
1. Y= -3/4x - 2
2. Y= 5/6x + 8
pshichka [43]3 years ago
4 0
Y=mx+b

Y=5/6+8
Hope this helps
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Demetrius deposits $120 iinto his account. One week later he withdraws $36. Write an addition sentence to represent this situati
Zolol [24]

Answer:

Demetrius's account is $84 higher after the two transactions

Step-by-step explanation:

Let

x -----> original amount in Demetrius's account

y ----> amount in Demetrius's account after the deposit and the withdraws

we know that

The amount in Demetrius's account after the two transactions must be equal to the original amount in Demetrius's account plus the deposit minus the withdraws

so

y=x+120-36

y=x+\$84

therefore

Demetrius's account is $84 higher after the two transactions

3 0
3 years ago
What’s 2+5 x 85?<br> Talk to me in the comments!!<br> I’m bored
neonofarm [45]

Answer:

i don know  the answer but heyyyyy

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In AKLM, m = 1.2 cm, k = 5.1 cm and
Elodia [21]

Answer:

  4.2 cm

Step-by-step explanation:

The law of cosines is applicable.

  l² = k² +m² -2km·cos(L)

  l² = 5.1² +1.2² -2·5.1·1.2·cos(35°) ≈ 17.4236

  l ≈ √17.4236

  l ≈ 4.2 . . . cm

4 0
3 years ago
How much of a stick of butter is 1/2 cup?
V125BC [204]
1 stick of butter :))))))))))))))
4 0
3 years ago
A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
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