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malfutka [58]
3 years ago
7

Answer the second question only please :D

Mathematics
2 answers:
irakobra [83]3 years ago
4 0
1. Y= -3/4x - 2
2. Y= 5/6x + 8
pshichka [43]3 years ago
4 0
Y=mx+b

Y=5/6+8
Hope this helps
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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

6 0
3 years ago
Describe a sequence of transformations that maps triangle ABC onto triangle A"B"C"<br> Help please?
monitta

the answer is reflection

7 0
3 years ago
When Sarah turned 18, she took $500 from her savings and opened a
Montano1993 [528]

The worth of Sarah's investment when she is 68 is $14,728.51.

<h3>What is the worth of the investment?</h3>

The formula that can be used to determine the worth of the investment is:

FV = P (1 + r)^n

FV = Future value

P = Present value

R = interest rate

N = number of years = 68 - 18 = 50

$500 x (1.07)^50 = $14,728.51

To learn more about future value, please check: brainly.com/question/18760477

6 0
2 years ago
What makes this equation true?<br><br> -2n + 1.8 = 3.2<br><br> Im so confused
fenix001 [56]

Answer:

18 = 3.2

Step-by-step explanation:

5 0
2 years ago
Trigonometry heeellllppp plzzzz​
algol [13]

Answer:

x ≈ 3.4 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin57° = \frac{opposite}{hypotenuse} = \frac{x}{4} ( multiply both sides by 4 )

4 × sin57° = x , thus

x ≈ 3.4 cm ( to 1 dec. place )

3 0
3 years ago
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