It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
the amount after 5 years using compound continuously is $135.03
Step-by-step explanation:
The computation of the amount after 5 years using compound continuously is as follows
= Principal × e^(rate × time period)
= $110 × e^(4.2% × 5)
= $110 × 1.227525065
= $135.03
Hence, the amount after 5 years using compound continuously is $135.03
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Answer:
5.58×10²⁴ atoms.
Step-by-step explanation:
From the question given above, the following data were obtained:
1 mole of silver = 107.9 g
Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
Number of atoms in a kilogram of silver =.?
Next, we shall convert 1 kg of silver to grams (g). This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Finally, we shall determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
107.9 g of silver contains 6.02×10²³ atoms.
Therefore, 1000 g of silver will contain = (1000 × 6.02×10²³) / 107.9 = 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Answer:
12 stores
Step-by-step explanation:
180 * 1/15 = 180/15 = 12
Answer:
The 6 Lego kits can be selected from the 9 available Lego kits in 84 ways.
Step-by-step explanation:
Use combinations to solve this problem.
Combination is defined as the selection of <em>r</em> elements from <em>n</em> distinct objects irrespective of the order. The objects cannot be replaced.
There are 9 Lego kits available.
And the total number of children is 6.
That is, we need to select 6 Lego kits from the 9 available Lego kits.
6 Lego kits can be selected from the 9 available Lego kits in 
ways.
Solving the combination as follows:
Thus, there are 84 ways to select 6 Lego kits from 9 available Lego kits.
