Hey!
So before trying to figure out the equation of the line, lets change -3y+4x = 9 into slope-intercept form:
-3y + 4x = 9
-3y = -4x + 9
y = (4/3)x - 3
Now that you have the equation in slope-intercept form we can find the equation of the line parallel to this. One thing that we are given from this equation is the slope of the line, the slope for two parallel lines are the same. So we know that the slope of the line is 4/3. We are also given another point on the line and we can plug this point in for y and x to find the y-intercept or b:
6 = (4/3)(-12) + b
6 = -16 + b
22 = b
Now that we know b, we have both the y-intercept and the slope so our equation would be:
y = (4/3)x + 22
Answer:
Its not a real number for the square roots of negative number
its not possible...
= -2 x -2 no... 2 x 2 no..... -2 x 2 yea but thats not square root anymore...
Step-by-step explanation:
Give me brainliest!!!
58 103 72
47 13 71
Hope I helped!
~ Zoe
Answer:
Compare the given equation of the circle (x - 1)² + (y -2)² = 2²
with standard form of circle: (x - h)² + (y - k)² = r²
Here, (h, k) is the center of the circle
and r is the radius of the circle.
Thus, The center of the circle is: (1, 2)
Also, for finding the point of intersections of (x - 1)² + (y -2)² = 2² and y = 2x + 2,
Substitute the value of y from equation of line in the equation of circle.
(x - 1)² + (2x + 2 - 2)² = 2²
⇒ (x - 1)² + (2x)² = 2²
⇒ x² + 1 - 2x + 4x² = 4
⇒ 5x² - 2x - 3 = 0
Applying Middle term splitting method
5x² - 5x + 3x - 3 = 0
⇒ 5x(x - 1) + 3(x - 1) = 0
⇒ (5x + 3)(x - 1) = 0
⇒ x =
and x = 1
Thus, we get coordinates:
and (1, 4)