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n200080 [17]
3 years ago
13

What is the measure of x? Angles are not necessarily drawn to scale. 63 PLEASE HELPPP

Mathematics
1 answer:
Andrei [34K]3 years ago
6 0

Answer:

help with what?

Step-by-step explanation:

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PLEASE HELP QUICK<br> What is the slope-intercept form of the linear equation 2x + 3y = 6?
Salsk061 [2.6K]

Answer:

y = - \frac{2}{3} x + 2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = 6 into this form

subtract 2x from both sides

3y = - 2x + 6 ( divide all terms by 3 )

y = - \frac{2}{3} x + 2 ← in slope-intercept form


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3 years ago
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Hi. <br> I need to know how to-<br> write a radical expression as a radical exponent??
Lady bird [3.3K]
You can check khan academy for help I’m sorry I don’t exactly know :(
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3 years ago
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I can’t find the fraction for 0.45
Andre45 [30]

Answer: 45/100

Step-by-step explanation:  .45 as a fraction is 45/100

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3 years ago
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To form 3 adjacent squares (as in the figure), 10 toothpicks are required. How many toothpicks are required to form 100 adjacent
Sonja [21]
<span>Let's say in general you want "n" adjacent squares. Each one needs a top, so that's n toothpicks. Each one needs a bottom, so that's another n toothpicks, and we're up to 2n total. You need one on the far left, and one on the far right, which brings us up to 2n + 2 toothpicks. Now we need to worry about the middle ones. But notice that you don't need n toothpicks for the interior because adjacent squares share. It turns out that you only need n-1. That brings us up to a grand total of 3n + 1 toothpicks, which would be 301 for n = 100.


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7 0
3 years ago
On any given day, the number of users, u, that access a certain website can be represented by the inequality 125-4530
Masteriza [31]

Answer:

Step-by-step explanation:

Our inequality is |125-u| ≤ 30. Let's separate this into two. Assuming that (125-u) is positive, we have 125-u ≤ 30, and if we assume that it's negative, we'd have -(125-u)≤30, or u-125≤30.

Therefore, we now have two inequalities to solve for:

125-u ≤ 30

u-125≤30

For the first one, we can subtract 125 and add u to both sides, resulting in

0 ≤ u-95, or 95≤u. Therefore, that is our first inequality.

The second one can be figured out by adding 125 to both sides, so u ≤ 155.

Remember that we took these two inequalities from an absolute value -- as a result, they BOTH must be true in order for the original inequality to be true. Therefore,

u ≥ 95

and

u ≤ 155

combine to be

95 ≤ u ≤ 155, or the 4th option

4 0
3 years ago
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