Answer:
1.25 m/s
Explanation:
m1v1+m2v2=m1v1f+m2v2f
(1425*13)+(1175*0)=(1425*v1f)+(1175*14.25)
18525+0=1425(v1f)+16743.75
1781.25=1425(v1f)
v1f=1.25 m/s
Answer:
Because 'distance per second' is a velocity, not an acceleration.
Explanation:
Because 'distance per second' is a velocity, not an acceleration. For example, at 1 m/s an object is travelling a distance of 1 metre every second. But a rate of acceleration is a steady increase in velocity. So at 1 m/s^2, an object's velocity is increasing by 1 m/s every second.
Answer:
Interface
Explanation:
This is a classic example of Interface technology.
An interface allows different software packages to communicate without re-entering data.
Here in this case also systems are able to communicate with one another without duplicating data entry. For example, practice management software and another for their electronic health record.
Answer:
1.04 s
Explanation:
The computation is shown below:
As we know that
t = t' × 1 ÷ (√(1 - (v/c)^2)
here
v = 0.5c
t = 1.20 -s
So,
1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)
1.20 = t' × 1 ÷ (√(1 - (0.5)^2)
1.20 = t' ÷ √0.75
1.20 = t' ÷ 0.866
t' = 0.866 × 1.20
= 1.04 s
The above formula should be applied
