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3 years ago

15

Can I have some help

1 answer:

Masja [62]3 years ago

4 0

Your answer is point F

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Object 1 has a mass of 3m and is moving to the right at a velocity of

andrew11 [14]

Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

6 0

2 years ago

Steam enters an adiabatic turbine at 5 MPa and 4500C and leaves at a pressure of 1.4 MPa. Determine the work output of the turbi

REY [17]

Answer:350.92 KJ/kg

Explanation:

Given the process is reversible adiabatic i.e it is isentropic

$P_1=5 MPa$

$T_1=4500 MPa$

$P_2=1.4 MPa$

From steam table

$h_1=3317.03KJ/kg$

For isentropic process $s_1=s_2$

at $P_2=1.4 MPa$

$s_2=6.82 KJ/kg-k$

$h_2=2966.11 KJ/kg$

Therefore Work output of the turbine per unit mass of steam is = $h_1-h_2$

=3317.03-2966.11

=350.92 KJ/kg

8 0

3 years ago

Identify the clean sources of energy.

sineoko [7]

Answer:

biomass, geothermal, hydropower, solar, and wind.

hope this helped!

6 0

2 years ago

Calculate the average induced voltage between the tips of the wings of a Boeing 747 flying at 940 km/hr above East Lansing. The

ANTONII [103]

Answer:

option (b)

Explanation:

B = 0.7 x 10^-4 T

v = 940 km/h = 940 x 5 / 18 = 261.11 m /s

l = 60 m

Th emotional emf is given by

e = B v l

e = 0.7 x 10^-4 x 261.11 x 60 = 1.096 V

e = 1.1 V

5 0

2 years ago

A thin film of alcohol (n = 1.36) lies on a flat glass plate (n = 1.51). When monochromatic light, whose wavelength λ can be cha

Shkiper50 [21]

Answer:

The thickness of the film, t = 470.59 nm

Explanation:

$\lambda_{film} = \frac{\lambda}{n_{film} }$

For constructive interference, the net phase change, $\phi = \phi_{2} - \phi_{1} = 2\pi m_{1}$

Then the thickness, $t = 0.5 \lambda_{film} m_{1}$

m₁ = 1,2,3........

$t = 0.5\frac{\lambda_{1} }{n_{film} } m_{1}$ ..............(i)

For destructive interference, the net phase change is $\phi = \phi_{2} - \phi_{1} = 2(m_{2} + 1)\pi$

m₂ = 1,2,3........

thickness, $t = 0.5\frac{\lambda_{1} }{n_{film} }(2 m_{2}+1)$ ..............(ii)

Equating (i) and (ii)

$0.5\frac{\lambda_{1} }{n_{film} } m_{1} = 0.5\frac{\lambda_{1} }{n_{film} }(2 m_{2}+1)$

$\frac{2m_{2} + 1}{2m_{1} } = \frac{\lambda_{1} }{\lambda_{2}} = \frac{640}{512}$

$\frac{2m_{2} + 1}{2m_{1} } = 1.25$ .............(iii)

From (iii), When m₁ =2, m₂ = 2

The thickness , $t = 0.5\frac{\lambda_{1} }{n_{film} } m_{1}$ then becomes

$t = 0.5\frac{640}{1.36} *2$

t = 470.59 nm

7 0

3 years ago