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svet-max [94.6K]
3 years ago
15

Please help me it's URGENT (#10 btw and also how do I solve for time​

Physics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer:

t = 12s

Explanation:

Given:

v-initial = 0 m/s

x = 360 m

a = 5.0 m/s^2

Solve:

x = (v-initial)t + 1/2(a*t^2)

360 = 0t + 1/2 (5.0t^2)

360 = 2.5 t^2

144 = t^2

t = sqrt(144) = 12

Therefore, it takes 12 seconds.

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Which of the following best defines insulator?
aliya0001 [1]

Answer:

A substance with low ability or no ability to conduct energy.

Such as Rubber,Silicone,Plastic

6 0
3 years ago
calculate the mass of displaced water when a piece of 30cm Iceberg with surface area 1000 cm^2 floats on water density of ice is
sweet [91]

Vi = As * h = 1000 * 30 = 30,000 cm^3 = Vol. of the ice.

Vb = (Di/Dw) * Vi = (0.9/1.0) * 30,000 = 27,000 cm^3 = Vol. below surface - Vol. of water displaced.

27,000cm^3 * 1g/cm^3 = 27,000 grams = 27 kg = Mass of water displaced.

3 0
3 years ago
When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam
iris [78.8K]

Answer:

Explanation:

Given:

U1 = 1.6 m/s

U2 = -1.1 m/s

M1 = 1850 kg

M2 = 1400 kg

V1 = 0.27 m/s

Using momentum- collision equation,

M1U1 + M2U2 = M1V1 + M2V2

1850 × 1.6 - 1400 × 1.1 = 1850 × 0.27 + 1400 × V2

1420 = 499.5 + 1400V2

V2 = 0.6575 m/s

B.

KE = 1/2 × MV^2

KEa1 + KEa2 = KEb1 + KEb2

Delta KE = KE2 - KE1

KEa1 = 2368 J

KEb1 = 847 J

KEa2 = 67.433 J

KEb2 = 302.6 J

KE1 = KEa1 + KEb1

= 3215 J

KE2 = 370.033 J

Delta KE = -2845 J.

5 0
3 years ago
A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is
Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration a_{c} is given by the following equation:  

a_{c}=\frac{V^{2}}{r} (1)

Where:  

a_{c}=17 m/s^{2} is the <u>centripetal acceleration</u>

V is the<u> tangential speed</u>

r=12 m is the <u>radius</u> of the circle

Isolating V from (1):

V=\sqrt{a_{c}r} (2)

V=\sqrt{(17 m/s^{2})(12 m)}

<u />

Finally:

V=14.28 m/s This is the girl's tangential speed

3 0
3 years ago
A 7.8 µF capacitor is charged by a 9.00 V battery through a resistance R. The capacitor reaches a potential difference of 4.20 V
Vaselesa [24]

Answer:

655128 ohm

Explanation:

C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F  

V₀ = Voltage of the battery = 9 Volts  

V = Potential difference across the battery after time "t" = 4.20 Volts  

t = time interval = 3.21 sec  

T = Time constant

R = resistance  

Potential difference across the battery after time "t" is given as  

V = V_{o} (1-e^{\frac{-t}{T}})

4.20 = 9 (1-e^{\frac{-3.21}{T}})

T = 5.11 sec  

Time constant is given as  

T = RC  

5.11 = (7.8 x 10⁻⁶) R  

R = 655128 ohm

3 0
3 years ago
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