Please help! Kiki makes a table to compare the particles in a magnesium atom to those in a magnesium ion. She knows that a magne
2 answers:
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The time between the successive crusts will give the time period of the wave.
So, the time period, T of the given wave is 0.2 s.
The frequency of a wave is the reciprocal of its time period. That is,
Frequency, ν =
=
= 5 Hz
Thus, the frequency of the given travelling periodic wave is 5 Hz.
Answer:
The acceleration of the electron is 1.457 x 10¹⁵ m/s².
Explanation:
Given;
initial velocity of the emitted electron, u = 1.5 x 10⁵ m/s
distance traveled by the electron, d = 0.01 m
final velocity of the electron, v = 5.4 x 10⁶ m/s
The acceleration of the electron is calculated as;
v² = u² + 2ad
(5.4 x 10⁶)² = (1.5 x 10⁵)² + (2 x 0.01)a
(2 x 0.01)a = (5.4 x 10⁶)² - (1.5 x 10⁵)²
(2 x 0.01)a = 2.91375 x 10¹³
Therefore, the acceleration of the electron is 1.457 x 10¹⁵ m/s².
Answer:
C₂ = 2.22 KJ/kg °C
Explanation:
Since, both objects are in thermal contact. Therefore, the law of conservation of energy tells us that:
where,
m₁ = mass of ice = 1 kg
C₁ = specific heat of ice = 2.04 KJ/kg.°C
ΔT₁ = Change in Temperature of Ice = -8.88°C - (-24°C) = 15.12°C
m₂ = mass of metal block = 1 kg
C₂ = specific heat of metal = ?
ΔT₂ = Change in Temperature of Metal Block = 5°C - (-8.88°C) = 13.88°C
Therefore, using these values in the equation, we get:
<u>C₂ = 2.22 KJ/kg °C</u>