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Katyanochek1 [597]
3 years ago
11

Make a list of principle of lever.

Physics
2 answers:
vivado [14]3 years ago
8 0

Answer:

The force applied to make the object move

Artyom0805 [142]3 years ago
5 0

Answer:

input work = output work

E * ED = L* LD

Explanation:

The principle of lever is that input work is always equal to output work .

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The mass of the earth is 6x10^24 kg and its radius is 6400 km.What is the mass of a man weighing 977 N in a spring balance.​
Lina20 [59]

g will be equal to 9.775, f=mg

So m= f/g

=99.95

4 0
3 years ago
Melissa uses bags of mulch that way 40 pounds each. She needs to carry 10 bags to her truck. She usually carries one bag at a ti
arsen [322]
No. She would be doing the same amount of work that way. Work is defined to be equal to the force multiplied by the distance. Carrying two bags at a time would cause her to exert twice the effort, so the total amount of work done in the end would still be the same.
4 0
3 years ago
A 2,000 kg car is moving at 15m/s when it collides with a 1200kg car sitting still. Briefly compare the impulse imparted on the
I am Lyosha [343]

impulse = F × t

The greater the impulse exerted on something, the greater will be the change in momentum.

impulse = change in momentum

Ft = ∆(mv)

4 0
4 years ago
Read 2 more answers
WILL GIVE BRAINLIEST IF CORRECT!
Norma-Jean [14]

Answer:

10000N

Explanation:

Given parameters:

Mass of the car  = 1000kg

Acceleration = 3m/s²

g  = 10m/s²

Unknown:

Weight of the car  = ?

Solution:

To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.

 Weight  = mass x acceleration due to gravity

So;

    Weight  = 1000 x 10  = 10000N

5 0
3 years ago
Starting from rest, a 2.3x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts
Harman [31]

Answer:

3.13 m/s

Explanation:

From the question,

Since the flea spring started from rest,

Ek = W................... Equation 1

Where Ek = Kinetic Energy of the flea spring, W = work done on the flea spring.

But,

Ek = 1/2mv²............ Equation 2

Where m = mass of the flea spring, v = flea's speed when it leaves the ground.

substitute equation 2 into equation 1

1/2mv² = W.................... Equation 3

make v the subject of the equation

v = √(2W/m)................. Equation 4

Given: W = 3.6×10⁻⁴ J, m = 2.3×10⁻⁴ kg

Substitute into equation 4

v = √[2×3.6×10⁻⁴ )/2.3×10⁻⁴]

v = 7.2/2.3

v = 3.13 m/s

Hence the flea's speed when it leaves the ground  = 3.13 m/s

4 0
3 years ago
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