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Katyanochek1 [597]
2 years ago
11

Make a list of principle of lever.

Physics
2 answers:
vivado [14]2 years ago
8 0

Answer:

The force applied to make the object move

Artyom0805 [142]2 years ago
5 0

Answer:

input work = output work

E * ED = L* LD

Explanation:

The principle of lever is that input work is always equal to output work .

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The part of earth where all living things are found is called the
Amanda [17]

Answer:

Hey Dude....

Explanation:

This is ur answer.....

<em>The biosphere is made up of the parts of Earth where life exists. The biosphere extends from the deepest root systems of trees to the dark environment of ocean trenches, to lush rain forests and high mountaintops.</em>

Hope it helps!

Brainliest pls!

Follow me! :)

5 0
2 years ago
Suppose someone pours 0.250 kg of 20.0ºC water (about a cup) into a 0.500-kg aluminum pan with a temperature of 150ºC. Assume th
Troyanec [42]

Answer : The temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of aluminium = 0.90J/g^oC

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of aluminum = 0.500 kg = 500 g

m_2 = mass of water = 0.250 kg  = 250 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of aluminum = 150^oC

T_2 = initial temperature of water = 20^oC

Now put all the given values in the above formula, we get:

500g\times 0.90J/g^oC\times (T_f-150)^oC=-250g\times 4.184J/g^oC\times (T_f-20)^oC

T_f=59.10^oC

Therefore, the temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

8 0
3 years ago
A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude
marusya05 [52]

Answer:

a) 8.83*10⁵ m/s  b) 2.80*10⁶ m/s

Explanation:

a) Assuming no other forces acting on the proton, the acceleration on it is produced by the electric field.

By definition, the  force due to the electric field is as follows:

F = q*E = e*E (1)

where e is the elementary charge, the charge carried by only one proton, and is e = 1.6*10⁻¹⁹ C.

According to Newton's 2nd law, this force is at the same time, the product of the mass of the proton, times the acceleration a:

F = mp*a (2)

From (1) and(2), being left sides equal, right sides must be equal too:

F = e*E = mp*a

Solving for a:

a = \frac{e*E}{mp} =\frac{1.6e-19C*1.36e5N/C}{1.67e-27kg} =1.3e13 m/s2

⇒ a = 1.3*10¹³ m/s²

As we have the value of a (which is constant due to the field is uniform), the displacement x, and we know that the initial velocity is 0, in order to get the value of the speed, we can use the following kinematic equation:

vf^{2} -vo^{2} = 2*a*x

Replacing by v₀ = 0, a= 1.3*10¹³ m/s² and  x = 0.03 m, we can find vf as follows:

vf =\sqrt{2*(1.3e13 m/s2)*0.03m} = 8.83e5 m/s

⇒ vf = 8.83*10⁵ m/s

b) We can just repeat the equation from above, replacing x=0.03 m by x=0.3 m, as follows:

vf =\sqrt{2*(1.3e13 m/s2)*0.3m} = 2.80e6 m/s

⇒ vf = 2.80*10⁶ m/s

4 0
3 years ago
A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of
disa [49]

The average acceleration is

\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}

5 0
3 years ago
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Mamont248 [21]

Answer:

1.bandages

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6 0
2 years ago
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