Ask question

Ask question

All categories

2 years ago

7

Copper metal has a specific heat of 0.385 J/goC. Calculate the amount of heat required to raise the temperature of 22.8 g of Cu

from 20.0 oC to 875 oC.

1 answer:

Liula [17]2 years ago

4 0

Answer is equal to 7.51 kJ

Q=mc(delta)T

You might be interested in

8. Which of the following statements about noble gases is correct?

Tanya [424]

Answer:

C.

Explanation:

Noble gases are stable and already have a full outter shell therefore don't tend to lose or gain any electrons.

8 0

3 years ago

On the first day of your new job as a chemist, you are given a bottle of magnesium sulfate and asked to make 30 mL of 0.3 M MgSO

Lady bird [3.3K]

Answer:

The answer to your question is 15500 mg of MgSO₄ 7H₂O

Explanation:

Data

Volume = 30 ml

Concentration = 0.3 M

Formula MgSO4∗7H2O

Process

1.- Calculate the number of moles needed

Molarity = moles / volume

Solve for moles

moles = Molarity x volume

Substitution

moles = 0.3 x 0.03 l

moles = 0.009 moles of MgSO₄

2.- Calculate the molecular mass of MgSO4∗7H2O

molecular mass = 24 + 32 + 64 + 14 + 112

= 246 g

3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7

4.- Calculate the amount of MgSO4∗7H2O

$0.009 mol of MgSO4 \frac{7 MgSO4 7H2O}{1 mol MgSO4} \frac{246 g MgSO4 7H2O}{1 mol MgSO4 7H2O}$

Simplification

15.5 g = 15500 mg

5 0

3 years ago

Copper crystallizes in a face-centered cubic lattice (the Cu atoms are at the lattice points and at the face centers). If the de

Delvig [45]

Answer:

The unit cell edge lenght in pm is equal to 361 pm

Explanation:

Data provided:

ρ=Copper density=8.96 g/cm3

Atomic mass of copper=63.54 g/mol

Atoms/cell=4 atoms (in theory)

Avogadro's number=6.02x $10^{23}$ atoms/mol

Since copper has a cubic structure, its cell volume is equal to $a^{3}$ , which can be obtained through the relationship:

cell volume= $\frac{(atoms/cell)(atomic mass)}{(density)(Avogadros number)}$

Substituting the values:

cell volume= $\frac{(4 atoms)(63.54 g/mol)}{(8.96 g/cm3)(6.02x10^{23}) }=4.71x10^{-23}cm^{3}$

clearing, we have:

a= $\sqrt[3]{4.71x10^{-23}cm^{3} }=3.61x10^{-8}cm$

We convert from centimeter to picometer, 1cm=1x $10^{10}$ pm

a= $3.61x10^{-8}cmx\frac{1x10^{10}pm }{1cm} =361 pm$

8 0

3 years ago

Define the term organic farming<br><br>

wolverine [178]

Answer:

is agriculture that makes healthy food,healthy soil,healthy plants and healthy environments a priority,along with crop productivity

5 0

2 years ago

A sample of Cd(OH)2 is added to pure water and allowed to come to equilibrium at 25ºC. The concentration of Cd +2 = 1.7 x 10 -5M

Archy [21]

Answer:

$Ksp=2.0x10^{-14}$

Explanation:

Hello there!

In this case, given the solubilization of cadmium (II) hydroxide:

$Cd(OH)_2(s)\rightleftharpoons Cd^{2+}(aq)+2OH^-(aq)$

The solubility product can be set up as follows:

$Ksp=[Cd^{2+}][OH^-]^2$

Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

$Ksp=(1.7x10^{-5})(3.4x10^{-5})^2\\\\Ksp=2.0x10^{-14}$

Regards!

3 0

3 years ago