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Galina-37 [17]
3 years ago
13

Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr

ed to as covellite. If a sample of the ore containing 12.5% covellite is exposed to oxygen under high temperatures, copper (II) oxide and sulfur dioxide will form. What is the yield of copper (II) oxide if 1.00 kg of the original ore is processed and the expected yield is 90%
Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

m_{CuO}=93.6gCuO

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO

Regards.

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andriy [413]

Answer:

50 g of S are needed

Explanation:

To star this, we begin from the reaction:

S(s) + O₂ (g) →  SO₂ (g)

If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.

According to stoichiometry, we can determine the moles of sulfur dioxide produced.

100 g. 1mol / 64.06g = 1.56 moles

This 1.56 moles were orginated by the same amount of S, according to stoichiometry.

Let's convert the moles to mass

1.56 mol . 32.06g / mol = 50 g

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<u>Answer:</u> The reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

<u>Explanation:</u>

Mole ratio is defined as the ratio of the amount of moles of two substances that are participating in a chemical reaction.

In the given chemical equation:

2Fe+3Cl_2\rightarrow 2FeCl_3

The reactants are Fe and Cl_2 and the product is FeCl_3

The mole ratio is basically the stoichiometric ratio of the chemical compounds taking part in a chemical reaction.

The mole ratio of reactants is stoichiometric ratio of Fe and Cl_2, which is:

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Hence, the reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

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Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:

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Now, we infer the halogen is added to the carbon atom with the most carbon atoms next to it, in this case, carbon #2, in order to write the following product:

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