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Galina-37 [17]
3 years ago
13

Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr

ed to as covellite. If a sample of the ore containing 12.5% covellite is exposed to oxygen under high temperatures, copper (II) oxide and sulfur dioxide will form. What is the yield of copper (II) oxide if 1.00 kg of the original ore is processed and the expected yield is 90%
Chemistry
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

m_{CuO}=93.6gCuO

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO

Regards.

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527.184 J of heat is removed from a 21 g water sample if it is cooled from 34.0 ° C to 28.0 ° C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When the heat added or removed from a substance causes a change in temperature in it, this heat is called sensible heat.

In other words, the sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a change in temperature without there being a change in physical state (solid, liquid or gaseous). The equation that allows to calculate this heat exchange is:

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Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT=Tfinal-Tinitial is the change in temperature.

In this case:

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Replacing:

Q= 4.184 \frac{J}{g*C} * 21 g* (-6 C)

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To lower the temperature, heat has to be given, for that the final temperature must be lower than the initial temperature; and it receives the name of transferred heat and has a negative value, as in this case.

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