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Maru [420]
3 years ago
11

ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST

Chemistry
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

There are four electrons

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A sample of ammonia gas was allowed to come to equilibrium at 400 K. 2NH3(g) <----> N2(g) 3H2(g) At equilibrium, it was fo
Karolina [17]

Answer:

0.327 M

Explanation:

Step 1: Write the balanced equation

2 NH₃(g) ⇄ N₂(g) + 3H₂(g)

Step 2: Make an ICE chart

        2 NH₃(g) ⇄ N₂(g) + 3 H₂(g)

I              x             0            0

C          -2y            +y         +3y

E         x-2y             y           3y

Step 3: Find the value of y

The concentration of N₂ at equilibrium is 0.0161 M. Then,

y = 0.0161

Step 4: Find the value of x

The concentration of NH₃ at equilibrium is 0.295 M. Then,

x-2y = 0.295

x-2(0.0161) = 0.295

x = 0.327

8 0
3 years ago
Which statement most accurately describes the behavior of a catalyst?
Elodia [21]
The a answer to the statement is between B and D
3 0
3 years ago
How many grams of CO are needed to react with an excess of Fe2O3 to produce (210.3 g Fe) 209.7 g Fe? Show your work.
Fed [463]

Explanation:

3CO(g)+Fe_2O_3(s)\rightarrow 2Fe(s)+3CO_2(g)

1)Mass of CO when 210.3 g of Fe produced.

Number of moles of Fe in 210.3 g=

\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}

=\frac{210.3}{55.84 g/mol}=3.76 mol

According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.76 moles of Fe will be obtained from : \frac{3}{2}\times 3.76 moles of CO that is 5.64 moles.

Mass of CO in 5.64 moles =

\text{Number of moles}\times \text{molar mass of CO}=5.46\times 28 g/mol=157.92 g

2)Mass of CO when 209.7 g of Fe produced.

Number of moles of Fe in 209.7 g=

\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}

=\frac{209.7}{55.84 g/mol}=3.75 mol

According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.75 moles of Fe will be obtained from : \frac{3}{2}\times 3.75 moles of CO that is 5.625 moles.

Mass of CO in 5.625 moles =

\text{Number of moles}\times \text{molar mass of CO}=5.625\times 28 g/mol=157.5 g

4 0
3 years ago
Read 2 more answers
How is a battery and a banana the same when considering energy?
emmainna [20.7K]

A battery and a banana are the same when considering energy:

A battery when connected to a device produces electro-chemical reactions and contains one or more cells. The same thing can be tried out with fruits also. There are many fruits which can be taken into account. A lemon shows less amount of voltage when seen through a multimeter rather than a banana which shows a higher voltage. This was because of the acid present in the a fully ripped banana. The acid is called ascorbic acid. This acid has a higher pH level than compared to the pH of the citric acid found in lemon.  

This shows that a banana plant is not so expensive and reliable for the production of renewable energy and a battery is also inexpensive, reliable and stable.

4 0
3 years ago
**PLEASE HELP WITH SCIENCE**
fgiga [73]

it has an electrons in a fixed path together on energy levels.

5 0
3 years ago
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