1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maru [420]
3 years ago
11

ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST

Chemistry
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

There are four electrons

You might be interested in
What happens to the density of the air in the balloon as it is heated?
dexar [7]
Hope it helped you.

7 0
3 years ago
A balloon contains 269.7 L of helium at 6.12ºC and 1.00 atm. What is the temperature (in ºC) of the gas if the volume has increa
MatroZZZ [7]

Answer:

T2= 7.3°C

Explanation:

To solve this problem we will use Charles law equation i.e,

V1/T1 = V2/T2    

Given data

V1 = 269.7 L

T1 = 6.12 °C

V2= 320.4 L

T2=?

Solution:

Now we will put the values in equation

269.7 L / 6.12°C  = 320.4 L / T2

T2=  320.4 L × 6.12°C/ 269.7 L

T2= 1960.85 °C. L /269.7 L

T2= 7.3°C

3 0
3 years ago
if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

8 0
3 years ago
Omg I’ve been stressing for the past minutes can someone please help me
Alona [7]

Answer:

I think it would be the last answer

Explanation:

5 0
3 years ago
Read 2 more answers
Please help I need these answers
Burka [1]

Answer:

2 a

element pure form cannot broken down

3 b

Chemical change chemical R×N

(R×N = reaction)

4c homogeneous solution

Yield = Yield (reaction yield): A measure of a chemical reaction's efficiency, as a ratio of moles of product to moles of reactant. Usually expressed as a percentage. % Yield = Moles of product.

Explanation:

5 0
3 years ago
Other questions:
  • The table below shows two types of electromagnetic waves and three random applications of electromagnetic waves.
    13·2 answers
  • What is number one I need help
    9·1 answer
  • How many grams of cs in a sample of cs that contains the same number of moles as a 109 gram sample of sn
    11·1 answer
  • Which one of these statements would be considered a hypothesis? *
    15·2 answers
  • Hydrogen and helium in the universe were formed by which of these phenomena?
    11·1 answer
  • What are the characteristics found in transition elements ?​
    10·2 answers
  • I have similar chemical and physical properties to calcium but my molecular mass is lower, what element am I?
    11·1 answer
  • Place the following taxonomic ranks in order from most specific to least specific. A) Order; B) Phylum; C) Family
    10·2 answers
  • Given 5 Moles of H20. how many moles of O, are produced. Use the following Equation
    6·1 answer
  • Please help take all my points i need this asp
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!