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3 years ago

What effect does Earth’s spherical shape have on the amount of sunlight that reaches the equator?

Physics

1 answer:

vaieri [72.5K]3 years ago

5 0

Explanation:

The earth is spherical. So it's middle part is bulgjng outside. So more sunlight will be incident on the latitude near the equator. This will heat the air and it will rise up. This will cause high pressure difference and polar disturbances.

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A quantity of N2 occupies a volume of 1.4 L at 290 K and 1.0 atm. The gas expands to a volume of 3.3 L as the result of a change

lions [1.4K]

Answer:

$\rho = 0.50 g/L$

Explanation:

As we know that

PV = nRT

here we have

$P = 1.0 atm$

$P = 1.013 \times 10^5 Pa$

so we have

$V = 1.4 \times 10^{-3} m^3$

T = 290 K

now we have

$(1.013 \times 10^5)(1.4 \times 10^{-3}) = n(8.31)(290)$

$n = 0.06$

now the mass of gas is given as

$m = n M$

$m = (0.06)(28)$

$m = 1.65 g$

now density of gas when its volume is increased to 3.3 L

so we will have

$\rho = \frac{m}{V}$

$\rho = \frac{1.65 g}{3.3 L}$

$\rho = 0.50 g/L$

5 0

3 years ago

A projectile is launched at an angle of 30° from the horizontal and lands 69 s later at the same height from which it was launch

RideAnS [48]

Answer:

679.2 m/s

Explanation:

The formula for the time of flight of a projectile is given as,

T = 2usinФ/g ......................... Equation 1

Where T = Time of flight, u = initial velocity, Ф = angle of projectile to the horizontal, g = acceleration due to gravity.

make u the subject of the equation

u = Tg/2sinФ....................... Equation 2

Given: T = 69 s, Ф = 30°

Constant: g = 9.8 m/s²

Substitute into equation 2

u = (69×9.8)/(2×sin30)

u = 679.2 m/s.

Hence the initial speed of the projectile is 679.2 m/s

5 0

3 years ago

A characteristic controlled by one or more genes is called a what

Rama09 [41]

I believe the answer would be polygenic. The word translates to "multiple genes". This occurs when many genes make up one specific thing such as our hair color or eye color.

4 0

4 years ago

A satellite of mass ????=238 kg is in circular orbit around the Earth at an altitude above the earth's surface equal to the eart

lesya [120]

Answer:

Explanation:

a) the speed=

V=√2gr²/2r

=√gr/2

√10*637/2

V=31850m/s²

Magnitude of the acceleration

a=Gm/r²

10*238/(6370)²

2380/12740

=0.187

8 0

3 years ago

A string under a tension of 36 N is used to whirl a rock in a horizontal circle of radius 3.6 m at a speed of 16.12 m/s. The str

ExtremeBDS [4]

Answer:

6010.457N

Explanation:

Centripetal acceleration = a= V²/R

At a radius of 3.6m and velocity of 16.12m/s,

Acceleration is

a = 16.12²/ 3.6 = 72.182 m/s²

Force = Mass (m) * Acceleration (a)

36 = m * 72.182

m = 36/72.182

At breaking point

Radius = 0.468 m and Velocity = 75.1 m/s

a = V²/R = 75.1²/0.468

a = 12051.3 m/s

F = Mass(m) * Acceleration (a)

F = m * 12051.3

m = F/ 12051.3

Settings the ratio of mass equal

m = m

=> 36/72.182 = F/12051.3

F = 12051.3 * 36/72.182

F = 6010.457N

3 0

3 years ago