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Alex Ar [27]
3 years ago
9

HELP THIS IS URGENT! IT WOULD BE GREATLY APPRECIATED IF YOU ANSWER ALL BUT ONE IS FINE!

Physics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

1 both increase

2. highest to lowest A C D B

3 the kinetic energy is higher in the larger vehicle as they have the same speed

Explanation:

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Two astronauts are taking a spacewalk outside the International Space
Tems11 [23]

Answer:

im not sure

Explanation:

5 0
3 years ago
Determine the angle of an incline that would yield a constant velocity, given the coefficient of kinetic friction is 0.10.
azamat

Answer:

\theta=5.71^{o}

Explanation:

In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).

From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:

\sum F_{y}=0

-W_{y}+N=0

N=W_{y}

so:

N=mgcos(\theta)

now we can go ahead and do a sum of forces in the x-direction:

\sum F_{x}=0

the sum of forces in x is 0 because it's moving at a constant speed.

-f+W_{x}=0

-\mu_{k}N+mg sen(\theta)=0

-\mu_{k}mg cos(\theta)+mg sen(\theta)=0

so now we solve for theta. We can start by factoring mg so we get:

mg(-\mu_{k} cos(\theta)+sen(\theta))=0

we can divide both sides into mg so we get:

-\mu_{k} cos(\theta)+sen(\theta)=0

this tells us that the problem is independent of the mass of the object.

\mu_{k} cos(\theta)=sen(\theta)

we now divide both sides of the equation into cos(\theta) so we get:

\mu_{k}=\frac{sen(\theta)}{cos(\theta)}

\mu_{k}=tan(\theta)

so we now take the inverse function of tan to get:

\theta=tan^{-1}(\mu_{k})

so now we can find our angle:

\theta=tan^{-1}(0.10)

so

\theta=5.71^{o}

8 0
3 years ago
Forces always act alone. true or false
rjkz [21]
The statement "<span>Forces always act alone" is false. Force do not always act alone. It is always accompanied by another force that is always opposite to it. </span>
7 0
3 years ago
Read 2 more answers
What step did Mendel take to be sure that his pea plants did not self-pollinate?
Ipatiy [6.2K]

Answer:

it is made up of some theory

Explanation:

it is an artificial pollination

8 0
3 years ago
put the following in order of a full lunar month: full moon, new moon, 1st quarter, waxing gibbous, waning gibbous, waxing cresc
ASHA 777 [7]

The same cycle of phases repeats over and over and over and over and over again, so I could start the list with whatever phase I want, and build the list until I get to the same phase I  started with.  

But the cultures that track their months by the phases of the Moon (traditional Muslim, traditional Jewish, traditional Chinese) all start the new month with the New Moon, so I guess I'll start my list there too.

-- New Moon

-- Waxing Crescent

-- First Quarter

-- Waxing Gibbous

-- Full Moon

-- Waning Gibbous

-- Third Quarter

-- Waning Crescent

-- next New Moon

4 0
3 years ago
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