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How many moles of H20 are produced from 6.4 moles of NaOH?

lord [1]

Answer:

hey

Explanation:

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5 0

2 years ago

β‑Galactosidase (β‑gal) is a hydrolase enzyme that catalyzes the hydrolysis of β‑galactosides into monosaccharides. A 0.387 g sa

gtnhenbr [62]

Answer:

The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 0.602 mbar = 0.000602 bar

0.000602 bar = 0.000594 atm

(1 atm = 1.01325 bar)

i = Van't hoff factor = 1 (for non-electrolytes)

c = concentration of solute = ?

R = Gas constant = $0.0820\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273.15 +25]=298.15 K$

Putting values in above equation, we get:

$0.000594 atm=1\times c\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298.15 K\\\\c=2.4278\times 10^{-5} mol/L$

The concentration of solute is $2.4278\times 10^{-5} mol/L$

Volume of the solution = V =0.137 L

Moles of β‑Galactosidase = n

$C=\frac{n}{V(L)}$

$n=2.4278\times 10^{-5} mol/L\times 0.137 L$

$n=3.3261\times 10^{-6} mol$

To calculate the molecular mass of solute, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of β‑Galactosidase = $3.3261\times 10^{-6} mol$

Given mass of β‑Galactosidase= 0.387 g

Putting values in above equation, we get:

$3.3261\times 10^{-6} mol =\frac{0.387 g}{\text{Molar mass of solute}}\\\\\text{Molar mass of solute}=116,352.97 g/mol$

Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

3 0

2 years ago

Would fire extinguishers that produce Carbon Dioxide (CO) gas be more effective in

yarga [219]

Answer:

They would be more efficient in ground fires since carbon dioxide is much greater in mass then oxygen, so its affected by gravity .

Explanation:

7 0

3 years ago

How do ions in metals behave. There is picture pls help.

sveticcg [70]

Answer:

metal atoms lose electrons to form positive ions (cations ) non-metal atoms gain electrons to form negative ions (anions )

i agree with this answer from the person above me: Augustlonley

Explanation:

*throws leaves in his face* Hey you wake up!!

7 0

3 years ago

If 62.0 grams of magnesium metal (Mg) react with 55.5 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the ex

Alina [70]

The balanced chemical equation would be as follows:

Mg + O2 → MgO2

We are given the amounts of the reactants. We need to determine first which one is the limiting reactant. We do as follows:

62.0 g Mg (1 mol / 24.31 g ) = 2.55 mol Mg
55.5 g O2 ( 1 mol / 32 g ) = 1.74 mol O2 -----> consumed completely and therefore the limiting reactant

2.55 mol - 1.74 mol O2( 1 mol Mg / 1 mol O2 ) = 0.81 mol Mg excess

4 0

3 years ago

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