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Bess [88]
3 years ago
8

How many molecules are in 3cacl2

Chemistry
1 answer:
Travka [436]3 years ago
5 0

Answer:

The molar mass and molecular weight of 3CaCl2 is 332.952. 

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Reika [66]
Can't understand this. English Please!  :) :)
8 0
3 years ago
Calculate the molar mass of NH4NO3. Molar mass of NH4NO3 = g/mol.
bija089 [108]

The molar mass of NH4NO3 in g/mol is 80g/mol.

HOW TO CALCULATE MOLAR MASS:

The molar mass of a compound can be calculated by summing the atomic masses of its constituent elements.

In ammonium nitrate (NH4NO3), there are nitrogen, hydrogen, and oxygen elements.

  • Atomic mass of nitrogen = 14
  • Atomic mass of oxygen = 16
  • Atomic mass of hydrogen = 1

Molar mass of NH4NO3 = 14 + 1(4) + 14 + 16(3)

Molar mass of NH4NO3 = 80g/mol

  • Therefore, the molar mass of NH4NO3 in g/mol is 80g/mol.

Learn more about molar mass at: brainly.com/question/8101390?referrer=searchResults

4 0
2 years ago
Read 2 more answers
4. If the speed of an object increases, its kinetic energy
Studentka2010 [4]

Answer:

I think the answer is increases

8 0
2 years ago
please help me with Chem I ONLY HAVE 5 MINUTES if methane gas (CH4) flows at a rate of 0.25L/s, how many grams of methane gas wi
Nookie1986 [14]

Answer:

643g of methane will there be in the room

Explanation:

To solve this question we must, as first, find the volume of methane after 1h = 3600s. With the volume we can find the moles of methane using PV = nRT -<em>Assuming STP-</em>. With the moles and the molar mass of methane (16g/mol) we can find the mass of methane gas after 1 hour as follows:

<em>Volume Methane:</em>

3600s * (0.25L / s) = 900L Methane

<em>Moles methane:</em>

PV = nRT; PV / RT = n

<em>Where P = 1atm at STP, V is volume = 900L; R is gas constant = 0.082atmL/molK; T is absolute temperature = 273.15K at sTP</em>

Replacing:

PV / RT = n

1atm*900L / 0.082atmL/molK*273.15 = n

n = 40.18mol methane

<em>Mass methane:</em>

40.18 moles * (16g/mol) =

<h3>643g of methane will there be in the room</h3>
5 0
3 years ago
How much would the temperature of 275 g of water increase if 36.5 kj of heat were added?
Andrew [12]

<u>Answer:</u> The temperature increase will be 31.70°C.

<u>Explanation:</u>

To calculate the increase in the temperature of the system, we use the equation:

q=mc\Delta T

where,

q = Heat absorbed = 36.5 kJ = 36500J

m = Mass of water = 275 g

c = Specific heat capacity of water = 4.186J/g^oC

\Delta T = change in temperature = ? °C

Putting values in above equation, we get:

36500J=275\times 4.186J/g^oC\times \Delta T\\\\\Delta T=31.70^oC

Hence, the temperature increase will be 31.70°C.

8 0
3 years ago
Read 2 more answers
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