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4 years ago

Over the course of two years the top layer of soil at a Michigan farm is blown away

Chemistry

1 answer:

Colt1911 [192]4 years ago

4 0

For each of the situations below, state whether it describes erosion, weathering, or possibly both.

Answer:

Erosion

Explanation:

The blowing away of the top layer of the soil at a Michigan farm is best described as scenario that shows wind erosion.

Erosion is the removal of the top layer of the earth on which plant grows. In short is the washing away of soil by stream or blowing away by wind.

When soil is blow away, it is a pure case of erosion. The process of erosion usually follows weathering or sometime occurs together with it.

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Often times, the process of weathering and erosion occurs together. It is loose weathering products that are carried away during erosion.

In the soil layer at Michigan, the process of erosion by wind is current taking place by ablation.

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What is pH when 4.0 mL of 2.0 M barium hydroxide is added to 10.0 mL of 1.00 M nitric acid?

Anika [276]

Answer : The pH of the solution will be 13.63.

Solution:

Moles of hydroxide ions in barium hydroxide solution

$BaOH_2\rightarrow Ba^++2(OH)^-$

Number of moles = (concentration) $\times$ (volume in liters) ...(1)(1L=1000mL)

<em>2.0 M barium hydroxide in solution</em>

Number of moles of $Ba(OH)_2$ in 2.0 M solution $=2.0 M\times 0.004 L=0.008$ moles

If One mole of barium hydroxide gives two moles of hydroxide in solution then 0.008 moles will give:

Number of moles of $OH^-=(2)\times (0.008 mol)=0.016$ moles

Moles of $H^+$ ions in nitric acid

$HNO_3\rightarrow NO^{-}_{3}+H^+$

<em>In 1.00 M nitric acid solution</em>

Moles of nitric acid in 1.0 M solution $=(1.0 M)\times(0.010 L)=0.010$ moles

If one mole of nitric acid will give one moles of $H^+$ ion.

Then 0.010 moles of nitric acid in solution will give :

Number of moles of $H^+=(1)\times (0.010 mol)=0.010$ moles

Since , the reaction will be neutralization reaction, equal number of moles of $H^+$ will neutralize equal number of moles of $OH^-$

So,0.010 moles of $H^+$ will neutralize 0.010 moles of $OH^-$ in the solution

Remaining moles of $OH^-=0.016- 0.01=0.006$ moles

Concentration of $[OH^-]$ resulting solution

Resulting volume of the solution : 0.004 + 0.010 liters

Calculating $[OH^-]$ by using equation (1).

$[OH^-]=\frac{0.006}{0.004L+0.010 L}=0.4285 M$

$pOH=-log[OH^-]=-log(0.4285)=0.367$

$pH=14-pOH=14-0.367=13.633$

The pH of the solution will be 13.633.

8 0

4 years ago

Upper C upper O subscript 2 (g) plus upper H subscript 2 (g) right arrow Upper C upper O (g) plus upper H subscript 2 upper O (l

Dominik [7]

Hydrogen gas

Explanation:

Expression:

CO₂ + H₂ → CO + H₂O

Hydrogen gas in this reaction is oxidized in the reaction.

In this manner, it is the reducing agent in the reaction.

A reducing agent is the specie in a chemical reaction that undergoes the process of oxidation.

It is marked by:

Addition of oxygen to a specie
Removal of hydrogen from a specie
Loss of electron by an atom
Increase in oxidation number
Increase in number of electronegative atoms surrounding a specie.

Here we see that H₂ fits this criteria perfectly well.

CO₂ is the one reduced.

learn more:

Oxidizing agent brainly.com/question/5558762

#learnwithBrainly

8 0

4 years ago

Read 2 more answers

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QveST [7]

Answer:

I believe the answer would be Air

5 0

3 years ago

Read 2 more answers

Are tectonic plate boundaries the only locations where volcanoes can form

Bond [772]

No, volcanoes can form in hot areas and convergent zones.

6 0

4 years ago

Although coal is a complex mixture of substances, its elemental composition can be approximated by the formula <img src="https:/

Svetllana [295]

Answer:

The correct answer is option b.

Explanation:

$2C_{135}H_{96}O_9NS+313O_2\rightarrow 270CO_2+2NO_2+2SO_2+96H_2O$

Mass of coal burned = $1.00\times 10^6$ metric ton = 1.00\times 10^6\times 10^3 kg=10^9 kg[/tex]

1 metric ton = $10^3kg$

Molar mass of coal :

$135\times 12g/mol+96\times 1g/mol+9\times 16 g/mol+1\times 14 g/mol+1\times 32 g/mol=1906 g/mol=1.906 kg/mol$

1 g = 0.001 kg

Moles of coal ,n : $\frac{10^9 kg}{1.906 kg/mol}=5.247\times 10^8 mol$

If 2 moles of coal on combustion gives 270 moles of carbon dioxide than n moles of coal will give;

$5.247\times 10^8 mol\times \frac{270}{2}=7.083\times 10^{10} mol$ of carbon dioxide.

Molar mass of carbon dioxide gas = 44 g/mol = 0.044 kg/mol

Mass of $7.083\times 10^{10} mol$ of carbon dioxide:

$7.083\times 10^{10} mol\times 0.044 kg/mol=3.11\times 10^{11} kg$

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3 years ago