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Harlamova29_29 [7]
3 years ago
13

Which gas is used by divers and why

Chemistry
1 answer:
BARSIC [14]3 years ago
5 0
What they breathe is compressed air. Yes normal air that every one breathes. This is compressed to 200bar and can last for approx. half an hour depending on the diver. What is exhaled is is also the same, namely carbon dioxide. 
<span>Sometimes divers mix gases to different ratios to give themselves longer dive times. This is called 'Ni-trox', which means ( Nitrogen/ Oxygen mixture). The gases exhaled are slightly different. </span>
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I would say B.

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A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th
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Answer: 0,4278g of F and 0,4191g of Fe

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0,847 * 0,4949 = 0,4191g of Fe

This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

At the end, the sum of the elements masses should be the total mass of the compound.

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1. For each of the following, convert the word equation into a formula equation, BUT do not balance! (4 pts each = 12 pts)
daser333 [38]

Answer:

  • 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)

  • 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

  • 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

  • 2a) Calcium hydroxide and hydrogen gas

  • 2b) Tin(II) silicate and Lead(IV) permanganate

  • 2c) Magnesium oxide and water

  • 2d) No product

  • 2e) Mercury and iodine

  • 2f) Calcium chloride and iodine

  • 2g) Strontium phosphite and cesium nitride

  • 2h) Carbon dioxide, water, and sulfur dioxide

  • 2i) Iron oxide(III) and carbon dioxide

  • 2j) Magnesium acetate and hydrogen gas

  • 2k) Calcium iodide

Explanation:

1. For each of the following, convert the word equation into a formula equation, BUT do not balance!

a) Barium chlorate → Barium chloride + Oxygen

<u>1. Chemical formulas</u>

Barium chlorate:

  • It is a salt: an ionic compound.
  • Barium has oxidation state +2
  • Chlorate is the ion ClO₃⁻
  • Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
  • Chemical formula Ba(ClO₃)₂
  • It is solid: Ba(ClO₃)₂(s)

Barium chloride:

  • It is a salt: an ionic compount
  • Barium has oxidation state +2
  • Chlorine is in oxidation state -1
  • Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
  • BaCl₂
  • It is solid BaCl₂(s)

Oxygen:

  • It is a diatomic gas molecule
  • O₂(g)

<u />

<u>2. Write the unbalanced molecular equation:</u>

  • BaClO₃(s) → BaCl₂(s) + O₂(g)

b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride

<u>1. Chemical formulas</u>

Chlorine:

  • It is a diatomic gas molecule
  • Cl₂(g)

Potassum nitride

  • It is a salt
  • Potassium has oxidation state +1
  • Nitrogen is with oxidation state +3
  • Swap the oxidation states
  • K₃N
  • It is solid: K₃N(s)

Nitrogen:

  • It is a diatomic gas
  • N₂(g)

Potassium chloride

  • It is a salt (ionic compound)
  • Potassium has oxidation state +1
  • Chlorine is in oxidation state -1
  • Swap the oxidation numbers
  • KCl
  • It is solid: KCl(s)

<u>2. Write the unbalanced molecular equation</u>

<u />

  • Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate

<u>1. Chemical formulas</u>

Sodium nitride

  • It is a salt (ionic compound)
  • Sodium has oxidation state +1
  • Nitrogen is with oxidation state -3
  • Swap the oxidation numbers
  • Na₃N
  • It is in aqueous solution
  • Na₃N (aq)

Aluminum bromate

  • Salt
  • Aluminum has oxidation state +3
  • Bromate is the ion BrO₃⁻
  • Swap the oxidation states
  • Al(BrO₃)₃ (aq)

Aluminum nitride

  • Both Al and N have oxidation state 3, which simply
  • AlN(s). It is not soluble in water.

Sodium bromate

  • Na(BrO₃)₃ (aq)

<u>2. Write the unbalanced molecular equation</u>

  • Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

<h2>This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2></h2><h2>The attached file contains the complete answer.</h2>
Download pdf
4 0
3 years ago
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