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sukhopar [10]
2 years ago
8

As a liquid is added to a beaker, the pressure exerted by the liquid on the bottom of the beaker does what

Chemistry
1 answer:
ololo11 [35]2 years ago
5 0
So if you put a holo ball of paper in the water it sinks and as it sinks it gets smaller cuse pressure so it cuseus things to shrink cuse of pressure
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How can we find the volume of this fish tank? Please I needed but Good
r-ruslan [8.4K]
<h3><u>Answer;</u></h3>

Find the number of 1-foot cubes that fill the fish tank

<h3><u>Explanation;</u></h3>

Volume of a cuboid such as the fish tank is given by the product of length width and height;

Such that; Volume = length × width × height

Similarly, we can count the number of 1 foot cube that can fill the fish tank.

And since each cube has a volume of 1 cubic ft, then the number of cubes will be equivalent to the volume of the fish tank in cubic ft.

5 0
2 years ago
Which statement is not true regarding nuclear reactions? Alpha, beta, and gamma are types of radiation. Nuclear reactions involv
svet-max [94.6K]
Alpha I believe not sure
7 0
3 years ago
ILL GIVE BRAINLIEST
Mice21 [21]

Answer:

Which of the following happens during a lunar eclipse?

Select one:

a. Earth casts a shadow on the moon.

<u>b. The moon casts a shadow on Earth. </u>

c. Earth stops revolving in its orbit.

d. Earth starts revolving around the moon.

Explanation:

7 0
3 years ago
If you have 100 ml of a 0.10 m tris buffer (pka 8.3) at ph 8.3 and you add 3.0 ml of 1.0 m hcl, what will be the new ph?
sukhopar [10]

The new pH is 7.69.

According to Hendersen Hasselbach equation;

The Henderson Hasselbalch equation is an approximate equation that shows the relationship between the pH or pOH of a solution and the pKa or pKb and the ratio of the concentrations of the dissociated chemical species. To calculate the pH of the buffer solution made by mixing salt and weak acid/base. It is used to calculate the pKa value. Prepare buffer solution of needed pH.

                       pH = pKa + log10 ([A–]/[HA])

Here, 100 mL  of  0.10 m TRIS buffer pH 8.3

                 pka = 8.3

         0.005 mol of TRIS.

∴  8.3 = 8.3 + log \frac{[0.005]}{[0.005]}

<em>    </em>inverse log 0 = \frac{[B]}{[A]}

   \frac{[B]}{[A]} = 1

Given; 3.0 ml of 1.0 m hcl.

           pka = 8.3

           0.003 mol of HCL.

pH = 8.3 + log \frac{[0.005-0.003]}{[0.005+0.003]}\\pH = 8.3 + log \frac{[0.002]}{[0.008]}\\\\pH = 8.3 + log {0.25}\\\\pH = 8.3 + (-0.62)\\pH = 7.69

Therefore, the new pH is 7.69.

Learn more about pH here:

brainly.com/question/24595796

#SPJ1

 

8 0
1 year ago
Consider dissolving sugar in water and magnesium sulfate in water. is any new substance being produced? what happens after sodiu
Olenka [21]

Answer:

Here's what I get  

Explanation:

1. Sugar

(a) Dissolving in water

The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.

2. Magnesium sulfate

(a) Dissolving in water

The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.

(b) Addition of sodium hydroxide

Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.

8 0
2 years ago
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