Do you agree or disagree for each one of them and provide evidence why??

Chemistry

1 answer:

sergiy2304 [10]2 years ago

6 0

Answer:

Disagree

Agree

Disagree

Explanation:

A chemical change is one in which a new kind of substance is formed. It is always accompanied by energy changes.

It is wrong to assert that all chemical changes are dangerous. In our body system, chemical changes are constantly happening.
Chemical changes shows the law of conservation of mass in that the amount of reactants and products are always the same.
Chemical reactions occur when two substances are chemically combined together.
Not all dissolution reaction are chemical changes. For example, when sugar dissolves in water, it is not a chemical change.

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Answer:

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A galvanic cell consists of a Cu(s)|Cu2+(aq) half-cell and a Cd(s)|Cd2+(aq) half-cell connected by a salt bridge. Oxidation occu

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Answer:

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

Explanation:

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The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

As it is given that cadmium acts as anode, it must be on the left hand side and copper must be on right hand side.

$Cd(s)|Cd^{2+}(aq) || Cu^{2+}(aq)|Cu(s)$

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In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?

Oksanka [162]

Answer:- C. H

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As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In $H_2O$ , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in $Cl^-$ is -1. On product side, the oxidation number of hydrogen in $H_2$ is zero and in $OH^-$ the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in $Cl_2$ is 0.