Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
Answer:
This is true because oxygen belongs to the non-metal part of the periodic table.
Answer:
acetyl CoA
Explanation:
The starting molecule for the krebs cycle is acetyl CoA.
I downloaded the picture and labelled it and attached it here. Also the answers I have from top to bottom are:
- Beaker
- Mixture (Suspension; filtration is only usually an effective method of
separation if the mixture is a liquid-solid suspension)
-Filter Funnel
-Filter Paper
-Residue
-Conical Flask
-Filtrate
If you need annotations let me know
Answer:
a substance which when dissolved with water makes H+ ions