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V125BC [204]
2 years ago
14

could you please explain operations with scientific notation using this example. 5 × 10³ + 4.3 × 10⁴ i dont understand how to so

lve it all . if you explain each step that would be great.
Chemistry
1 answer:
TEA [102]2 years ago
4 0

Explanation:

The scientific notation:

a\times10^k

where

1\leq a and k is integer.

We have the example:

(5\times10^3)+(4.3\times10^4)

You can write the numbers in a "normal" form:

5\times10^3=5\times1000=5000\\\\4.3\times10^4=4.3\times10000=43000

Make the sum:

5000+43000=48000

And next write it in the scientific notation:

48000=4\underbrace{8000}_{\leftarrow4}=4.8000\times10000=4.8\times10^4

<h3>Other method:</h3>

You can add numbers in scientific notation if the power of tens in both number is the same.

Therefore you must convert the first number:

5\times10^3=0.5\times10\times10^3=0.5\times10^4

Now, you can make the sum:

(5\times10^3)+(4.3\times10^4)=0.5\times10^4+4.3\times10^4=(0.5+4.3)\times10^4=4.8\times10^4

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Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC  = C = 0,50 J/gºC

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3 years ago
If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem
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Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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  • NaNO₃: 2 moles
  • Cu(NO₃)₂ : 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

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  • NaNO₃: 85 g/mole
  • Cu(NO₃)₂ : 187.54 g/mole
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Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
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<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}

<u><em>mass of NaCl= 1.739 grams</em></u>

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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