Answer:
15.4 g of sucrose
Explanation:
Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m
0.56°C / 1.86 m/°C = m → 0.301 mol/kg
m → molality (moles of solute in 1kg of solvent)
Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg
0.301 mol/kg . 0.150kg = 0.045 moles.
We determine the mass of sucrose, by the molar mass:
0.045 mol . 342 g/1mol = 15.4 g
Answer:
131.8 g.
Explanation:
- There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):
<u><em>d = m / V.</em></u>
d = 0.8787 g/ml.
V = 0.15 L x 1000 = 150 ml.
- ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
Answer:
There is no friction because of the mass.
Explanation:
The bigger box ran out of force to move so it hit the smaller box. (im in 7th grade and have the answer key)
Air has mass and density, and. cold air is denser than warm air.
The same amount of water as oil air
Blue is the color that can be best absorbed, as orange is the color seen.