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Nimfa-mama [501]
3 years ago
6

The isotope carbon-14 decays over time into nitrogen-14 with a half-life of 5,730 years. Suppose that you find a fossil that con

tains 1.25 grams of carbon-14 and 3.75 grams of nitrogen-14. How old is the fossil
Chemistry
1 answer:
KATRIN_1 [288]3 years ago
3 0

Answer:

11460 years

Explanation:

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life of the carbon

t = age of the fossil

No= amount of radioactive material originally present

N= amount of radioactive material present at time=t

No= mass of carbon + nitrogen = 5g

0.693/5730 = 2.303/t log (5/1.25)

1.21 ×10^-4 = 1.3866/t

t= 1.3866/1.21 ×10^-4

t= 11460 years

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Which of the following is a mixture? <br> Water (H2O), Gold, or Kool-Aid
babymother [125]

Sugar is an example of a compound, while koolaid is an example of a homogeneous mixture (more specifically, a solution). A compound is a combination of 2 or more different kinds of atoms chemically bonded in a set ratio. A mixture is a combination of 2 or more substances.

answer is koolaid is a mixture

6 0
4 years ago
How many electrons must Aluminum lose or gain to obtain a noble gas<br> electron configuration? *
BaLLatris [955]

Answer:

3 electrons

Explanation:

aluminum : [Ne]3s23p1 [ N e ] 3 s 2 3 p 1 . It loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.

6 0
3 years ago
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Many different localities are thought to be hotspots, found overlying mantle plumes, although scientists cannot agree on a defin
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(If this is correct, can I have Brainlist?)

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D) anomalous volcanoes such as those in Hawaii

4 0
2 years ago
A 33.0−g sample of an alloy at 93.00°C is placed into 50.0 g of water at 22.00°C in an insulated coffee-cup calorimeter with a h
Lostsunrise [7]

Answer:

THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K

Explanation:

Mass of alloy = 33 g

Initial temperature of alloy = 93°C

Mass of water = 50 g

Initail temp. of water = 22 °C

Heat capacity of calorimeter = 9.20 J/K

Final temp. = 31.10 °C

specific heat of alloy = unknown

specific heat capacity of water = 4.2 J/g K

Heat = mass * specific heat * change in temperature = m c ΔT

Heat = heat capcity * chage in temperature = Δ H * ΔT

In calorimetry;

Heat lost by the alloy = Heat gained by water + Heat of the calorimeter

                     mc ΔT = mcΔT + Heat capacity * ΔT

33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)

33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1

2042.7 C = 1911 + 83,72

C = 1911 + 83.72 / 2042.7

C = 1994.72 /2042.7

C =0.9765 J/g K

The specific heat of the alloy is 0.9765 J/ g K

5 0
3 years ago
7. Which of the following is a chemical property?
Goryan [66]

Answer:

It ability to react with oxygen.

Explanation:

Freezing point and hardness can be altered. Physical properties can also be reversed. Chemical properties on the other hand cannot. The product after reaction with an element never changes.

8 0
4 years ago
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