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3 years ago

How many electrons must Aluminum lose or gain to obtain a noble gas electron configuration? *

Chemistry

2 answers:

olganol [36]3 years ago

7 0

Answer:

it loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.

Explanation:

the guy on top beat me to it gg

BaLLatris [955]3 years ago

6 0

Answer:

3 electrons

Explanation:

aluminum : [Ne]3s23p1 [ N e ] 3 s 2 3 p 1 . It loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.

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d1i1m1o1n [39]

$Molar{Mass} H_{2}O_{2} =2*16.0+2*1.0= 34.0 g/mol

42.0 g H_{2}O_{2}* \frac{1 mol H_{2}O_{2}}{34.0 g H_{2}O_{2}} = 1.24 mol H_{2}O_{2}

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\\1.24 mol ---1.24 mol (from the problem)

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