How many electrons must Aluminum lose or gain to obtain a noble gas electron configuration? *

Chemistry

2 answers:

olganol [36]3 years ago

7 0

Answer:

it loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.

Explanation:

the guy on top beat me to it gg

BaLLatris [955]3 years ago

6 0

Answer:

3 electrons

Explanation:

aluminum : [Ne]3s23p1 [ N e ] 3 s 2 3 p 1 . It loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.

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kkurt [141]

Answer: The $\Delta H^o_{rxn}$ for the reaction is 72 kJ.

Explanation:

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According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)$ $\Delta H^o_{rxn}=?$